CODEWITHSUNDEEP
pythonarraysif-statement
Mateus Forcelini
Mateus Forcelini

Reputation: 121

Problems with numpy.any() for condition checking

I want to start an if condition checking all elements in a previously defined array, for example:

import numpy as np

f = np.zeros(5)
if f[i]<100
   #do something

where i is supposed to check all the elements of f. I believe there is an easy way to do this in python instead of creating a loop searching all elements, any help would be appreciated. Thanks in advance.

Edit: I tried to use the numpy.any() function but it seems is not working the way I thought, for example:

import numpy as np
z = np.array([1, 2000, 30000])
if np.any(z)>2:
   print('Something')

But the results return False

Upvotes: 0

Views: 226

Answers (1)

Mateus Forcelini
Mateus Forcelini

Reputation: 121

So I've made it with the any function:

import numpy as np

z = np.array([1, 2000, 3.2e+18])
if (any(x>1000 fo x in z)):
    # do something

Upvotes: 1

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