CODEWITHSUNDEEP
pythonarrayspython-3.xlistslice
Monali
Monali

Reputation: 43

Skipping n elements iteratively while slicing a list in python

I have a big array of 10573 elements and I want to group them into chunks but skipping two elements after each chunk.

I have the code to divide the list into chunks:

chunk_size= 109
for i in range(0, len(ints), chunk_size):
    chunk = ints[i:i+chunk_size]

But how do I skip or delete two elements from the big list iteratively, i.e., after attaining each chunk of size 109?

Is there a way to do that?

Upvotes: 0

Views: 299

Answers (2)

Barmar
Barmar

Reputation: 782693

Add 2 to the chunk size when using it in the iteration.

chunk_size= 109
for i in range(0, len(ints), chunk_size+2):
    chunk = ints[i:i+chunk_size]

Upvotes: 3

Tarik
Tarik

Reputation: 11209

Use modular arithmetics :

blocksize = chuncksize + 2
newints = [i for i in ints if i%blocksize < chuncksize]

The other way is to loop backward:

blocksize = chuncksize + 2
for i in range(len(ints), 0, -blocksize)
    ints.pop(i+chuncksize)
    ints.pop(i+chuncksize+1)

Note: Did not test.

Upvotes: 0

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