CODEWITHSUNDEEP
pythonwhile-loopuser-input
Veki
Veki

Reputation: 541

While Loop doesn't recognize multiple conditions

I am asking for an input from the user and it has to be a single character alphabet.

I tried this code.

ask = ''
while len(ask) != 1 and ask.isalpha() != True:
    ask = input(message).upper()

But this accepts any single number digit to break out of the while loop. I don't understand why.

I checked the ask.isalpha() on that single number and that returns False. So why does it break out of the loop.

Sorry for this question. This is very naïve but I couldn't find an answer.

Thank you.

Edit: Added the whole code.

Upvotes: 0

Views: 508

Answers (3)

DEAXParadox
DEAXParadox

Reputation: 1

There is different way to do it

# if you want user to enter upper case
while True:
    ask = input('message: ')
    if len(ask) == 1 and ask.isalpha() == True and ask.isupper() == True:
       break
       
# if you want to convert input to upper
while True:
    ask = (input('message: ')).upper()
    if len(ask) == 1 and ask.isalpha() == True:
       break

is this case all your condition are satisfied,

Upvotes: 0

U13-Forward
U13-Forward

Reputation: 71560

You need an or operation and not and to achieve what you want. Also, you need to take user input first time before entering the while loop.

So your code should be:

ask = input(message).upper()
while len(ask) != 1 or ask.isalpha() != True:
    ask = input(message).upper()

Upvotes: 1

posthumassouma
posthumassouma

Reputation: 3

You are using != which stand for not equal to so when you enter 1 digit number condition for while loop doesn't match so code stops. You should use == instead of !=.

Upvotes: 0

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