CODEWITHSUNDEEP
php
generalcb
generalcb

Reputation: 143

Get the next x days excluding weekends and show them all

I am having some difficulties display the next x number of days excluding weekends. The basic code is here which displays all days:

<?php

for($i = 0; $i < 8; $i++) {
    echo date('D M j', strtotime("$i day"));
}

?>

I cant then get it to do a continue:

<?php

for($i = 0; $i < 8; $i++) {
    $day = date('N', strtotime("$i day"));
    if($day == '6' || $day == '7') continue;
    echo date('D M j', strtotime("$i day"));
}

?>

But this obviously skips the weekends completely and I don't get x returned days. I have tried reducing the number by 1 but just get timeouts so guessing this is not the way to go.

Upvotes: 0

Views: 38

Answers (2)

digijay
digijay

Reputation: 1366

As CBroe already pointed out, use a variable for the number of days you want to iterate. When you get a saturday or sunday then increment that variable by one. E.g.

<?php

$x = 8;
for($i = 0; $i < $x; $i++) {
    $day = date('N', strtotime("$i day"));
    if($day == '6' || $day == '7') {
        $x++;
        continue;
    }
    echo date('D M j', strtotime("$i day"));
}

?>

The output would always be $x weekdays, for today it would be

Fri Jan 22Mon Jan 25Tue Jan 26Wed Jan 27Thu Jan 28Fri Jan 29Mon Feb 1Tue Feb 2

Upvotes: 1

Professor Abronsius
Professor Abronsius

Reputation: 33813

If you were to adopt the DateTime class you could do like this:

    $start=new DateTime();
    $end=new DateTime('now + 7days');
    $interval=new DateInterval('P1D');
    
    $start->sub( $interval );
    while( $start < $end ){
        $start->add( $interval );
        $N=intval($start->format('N'));
        if( $N > 0 && $N < 6 ){
            echo $start->format('l N Y-m-d H:i:s').'<br />';
        }
    }

Which yields output like:

Friday 5 2021-01-22 13:22:01
Monday 1 2021-01-25 13:22:01
Tuesday 2 2021-01-26 13:22:01
Wednesday 3 2021-01-27 13:22:01
Thursday 4 2021-01-28 13:22:01
Friday 5 2021-01-29 13:22:01

Upvotes: 1

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