Reputation: 8483
In my JPA Entity class I have:
@Entity
public class Booking {
@Id
@SequenceGenerator(name = "BOOKING", allocationSize = 1)
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "BOOKING")
private Integer id;
@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(nullable = false)
private User user;
// ...
}
In my GWT View I have:
MainRequestFactory.BookingRequest bookingRequest = reqFactory.bookingRequest();
BookingProxy bookingProxy = bookingRequest.create(BookingProxy.class);
UserProxy userProxy = bookingRequest.create(UserProxy.class);
userProxy.setId(12);
bookingProxy.setUser(userProxy);
Request<Void> persistRequest = bookingRequest.persist().using(bookingProxy);
persistRequest.fire(new Receiver<Void>() {
@Override
public void onSuccess(Void response) {
GWT.log("persisted");
}
});
/////////////////////
Users
and Bookings
persistence without the User Constraint works fine. But with the above code I want/have to assign the user with the ID "12" to a newly created booking. But I cannot assign a new booking to an already existing user ID 12. I get the following error:
[EL Warning]: 2011-07-05 18:48:45.464--UnitOfWork(267787945)--Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.3.0.v20110604-r9504): org.eclipse.persistence.exceptions.DatabaseException Internal Exception: org.firebirdsql.jdbc.FBSQLException: GDS Exception. 335544665. violation of PRIMARY or UNIQUE KEY constraint "INTEG_388" on table "USERS2"
It's because an user with the ID "12" already exists and JPA wants to create a new user with the same ID instead of just creating a new booking with the user ID "12" as its foreign key.
How can I tell RequestFactory
NOT to create a new user but instead just to assign the user ID of an already existing user to a new booking entry?
Upvotes: 1
Views: 861
Reputation: 55897
I think your analysis of the problem is correct.
Instead of creating a User, instead use an EntityManager find() or getReference() to retrieve the existing User item.
Upvotes: 4