Reputation: 319
Is there any built in function to compute the remainder of a variable in cvxpy? For instance, the following example code:
m = 3
n = 2
k = 5
A = cp.Variable((m,n),boolean=True)
B = np.ones((1,m))
C = np.ones(n)
constraints = []
objective = cp.Maximize((B@A%2)@C)
prob = cp.Problem(objective, constraints)
optimal_value = prob.solve()
gives error:
Exception has occurred: TypeError
unsupported operand type(s) for %: 'MulExpression' and 'int'
Because of the % operation
Upvotes: 0
Views: 265
Reputation: 16724
The remainder r = a mod n
, with a ≥ 0
, can be found as:
a = q*n + r (assume n is constant)
q ∈ {0,1,...} (integer variable, non-negative}
r ∈ {0,..,n-1} (integer variable between 0 and n-1)
This is just a linear constraint. See also: https://en.wikipedia.org/wiki/Modulo_operation.
Upvotes: 2