CODEWITHSUNDEEP
python-3.xlistfor-loopindexing
iTOOK Urzjob
iTOOK Urzjob

Reputation: 31

How to start for loop for a list at different starting index instead of [0]?

#creating a list named employees 

print(('#'*50).center(100,'~'))

employees=[['Name','Age','Department'],['John Mckee',28,'Sales'],['Lisa Crawford',29,'Marketing'],['Sujan patel',33,'HR']]

#print the top row of the matrix (the column names)

print(employees[0],'\n')

print('LISA DETAILS'.center(100,'-'))

#print only lisa details 

print('Name:',employees[2][0])
print('Age:',employees[2][1])
print('Department:',employees[2][2])



#print all employees details 

print('ALL DETAILS'.center(100,'-'))

print(employees)

#want to start for loop at Name:John,Age:28,Department:sales, instead of Name:Name,Age:Age,Department:Department 

for e in (employees):
        print('Name:',e[0])
        print('Age:',e[1])
        print('Department:',e[2])

Any way that I can start printing from second row (the employees basically) instead of first row (Name, Age, Department)?

I do, not know how I would go on about approaching for loop within a list at different position.

Upvotes: 0

Views: 504

Answers (2)

warownia1
warownia1

Reputation: 2925

If you need more pythonic approach to what @pakpe presented you can use list slicing

for e in employees[from_index:to_index]:
  ...

where from_index and to_index indicate boundaries and one of them may be omitted if not needed. This creates a copy of the array however. If you don't want to make copies then use itertools.islice()

for e in islice(employees, from_index, to_index):
  ...

unused parameter should be explicitly set to None in this case.

Upvotes: 2

pakpe
pakpe

Reputation: 5479

Instead of using a for-each loop, use a regular for loop that advances the index from 1 to len(employees):

for i in range(1, len(employees)):
    print('Name:',employees[i][0])
    print('Age:',employees[i][1])
    print('Department:',employees[i][2])

Upvotes: 1

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