CODEWITHSUNDEEP
androidandroid-studiokotlinjacksonjackson-databind
Stephenraj
Stephenraj

Reputation: 755

How to Deserialise the Jackson SNAKE CASE object mapper into CAMEL CASE data class model in Kotlin?

I have serialised the data class model "ProfileInfo" using

val jsonString = jacksonObjectMapper().setPropertyNamingStrategy(PropertyNamingStrategy.SNAKE_CASE).writeValueAsString(profileInfo)

but when I deserialise the jsonString into data class model using

val profileInfo: ProfileInfo = jacksonObjectMapper().readValue<ProfileInfo>(jsonString)

only the fields without underscores receiving the value. other fields with underscores assigned as null. Could anybody help me about how to deserialise using Jackson object mapper.

Upvotes: 3

Views: 4154

Answers (1)

Mafor
Mafor

Reputation: 10681

Each call to the jacksonObjectMapper() creates a new ObjectMapper, so either:

  • use the same object mapper for both, serialization and deserialization
val mapper = jacksonObjectMapper().setPropertyNamingStrategy(PropertyNamingStrategy.SNAKE_CASE)
val jsonString = mapper.writeValueAsString(profileInfo)
...
val profileInfo: ProfileInfo = mapper.readValue(jsonString)
  • configure property naming strategy for deserialization the same way, you are doing it for serialization
val profileInfo: ProfileInfo = jacksonObjectMapper().setPropertyNamingStrategy(PropertyNamingStrategy.SNAKE_CASE).readValue(jsonString)

Upvotes: 3

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