Reputation: 151
I have the Following 2d matrix :
int[][] states=new int[][]{{0,0},{0,1},{0,2},{1,0},{1,1},{1,2},{2,0},{2,1},{2,2}};
I want getting a 3d matrix with this output :
[0,1] | [0,2] | [1,0] | [1,1] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,2] | [1,0] | [1,1] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [1,0] | [1,1] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,1] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,1] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,1] | [1,2] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,1] | [1,2] | [2,0] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,1] | [1,2] | [2,0] | [2,1]
I tried the following code :
int[][] states=new int[][]{{0,0},{0,1},{0,2},{1,0},{1,1},{1,2},{2,0},{2,1},{2,2}};
int[][][] actions = new int[states.length][states.length][2];
// Remplissage :
for (int i = 0; i < states.length; i++) {
int k = 0;
for (int j = 0; j < states.length; j++) {
for (int c = 0; c < states[i].length; c++) {
actions[i][j] = states[j];
System.out.print(actions[i][j][c] + "\t");
}
}
System.out.println();
}
but I didn't get the desired result.
Upvotes: 0
Views: 111
Reputation: 51445
Here's the result of one of my test runs.
[0,1] | [0,2] | [1,0] | [1,1] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,2] | [1,0] | [1,1] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [1,0] | [1,1] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,1] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,2] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,1] | [2,0] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,1] | [1,2] | [2,1] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,1] | [1,2] | [2,0] | [2,2]
[0,0] | [0,1] | [0,2] | [1,0] | [1,1] | [1,2] | [2,0] | [2,1]
I broke the problem into pieces. First, I created the three-dimensional matrix. You need a nested for loop where you skip each element in turn.
Then I printed out the results of the three-dimensional matrix. I started with one pair. I wrote a method to produce [0,0]
. Then, I wrote a method to produce one line of the output. Finally, I wrote a method to produce the entire matrix.
Here's the complete runnable example.
public class CreateMatrix {
public static void main(String[] args) {
CreateMatrix cm = new CreateMatrix();
int[][] states = new int[][] { { 0, 0 }, { 0, 1 }, { 0, 2 },
{ 1, 0 }, { 1, 1 }, { 1, 2 }, { 2, 0 }, { 2, 1 }, { 2, 2 } };
int[][][] actions = cm.createActions(states);
System.out.println(cm.createTable(actions));
}
public int[][][] createActions(int[][] states) {
int[][][] actions = new int[states.length][states.length - 1][2];
for (int i = 0; i < states.length; i++) {
int k = 0;
for (int j = 0; j < states.length; j++) {
if (i != j) {
actions[i][k][0] = states[j][0];
actions[i][k][1] = states[j][1];
k++;
}
}
}
return actions;
}
public String createTable(int[][][] actions) {
String output = "";
for (int i = 0; i < actions.length; i++) {
output += createLine(actions[i]);
output += System.lineSeparator();
}
return output;
}
private String createLine(int[][] line) {
String output = "";
for (int i = 0; i < line.length; i++) {
output += createPair(line[i]);
if (i < (line.length - 1)) {
output += " | ";
}
}
return output;
}
private String createPair(int[] pair) {
return "[" + pair[0] + "," + pair[1] + "]";
}
}
Upvotes: 1