How to get folder path from file path with CMD

Question

I need path to the folder that contains cmd file. With %0 I can get the file name. But how to get the folder name?

c:\temp\test.cmd >> test.cmd

P.S. My current directory != folder of the script.

Answer 1

For .bat files you may want to use this command:

title %~f0

to put path and filename of the batch script into window title bar.

Answer 2

IMHO the simplest yet most powerful method to get the full path of a file is:

1. Start Notepad
2. Copy and Paste the following text: @echo %1 | clip 3
3. Save the file as "CopyAsPath.bat"

Now you can either

1. drag a file over that batch or
2. copy it into your SendTo menu folder (%USERPROFILE%\AppData\Roaming\Microsoft\Windows\SendTo)

Whether you follow the option 1 or the option 2, one millisecond later you can either

1. "press Ctrl-V" or
2. use "Right Mouse Click -> Paste"

to paste the full path+filename wherever you want.

Simple, powerful, and without using any external Windows tool.

Answer 3

For the folder name and drive, you can use:

echo %~dp0

You can get a lot more information using different modifiers:

%~I         - expands %I removing any surrounding quotes (")
%~fI        - expands %I to a fully qualified path name
%~dI        - expands %I to a drive letter only
%~pI        - expands %I to a path only
%~nI        - expands %I to a file name only
%~xI        - expands %I to a file extension only
%~sI        - expanded path contains short names only
%~aI        - expands %I to file attributes of file
%~tI        - expands %I to date/time of file
%~zI        - expands %I to size of file

The modifiers can be combined to get compound results:
%~dpI       - expands %I to a drive letter and path only
%~nxI       - expands %I to a file name and extension only
%~fsI       - expands %I to a full path name with short names only

This is a copy paste from the "for /?" command on the prompt.

Related

Top 10 DOS Batch tips (Yes, DOS Batch...) shows batchparams.bat (link to source as a gist):

C:\Temp>batchparams.bat c:\windows\notepad.exe
%~1     =      c:\windows\notepad.exe
%~f1     =      c:\WINDOWS\NOTEPAD.EXE
%~d1     =      c:
%~p1     =      \WINDOWS\
%~n1     =      NOTEPAD
%~x1     =      .EXE
%~s1     =      c:\WINDOWS\NOTEPAD.EXE
%~a1     =      --a------
%~t1     =      08/25/2005 01:50 AM
%~z1     =      17920
%~$PATHATH:1     =
%~dp1     =      c:\WINDOWS\
%~nx1     =      NOTEPAD.EXE
%~dp$PATH:1     =      c:\WINDOWS\
%~ftza1     =      --a------ 08/25/2005 01:50 AM 17920 c:\WINDOWS\NOTEPAD.EXE

Answer 4

This was put together with some edited example cmd

@Echo off

Echo ********************************************************
Echo *  ZIP Folder Backup using 7Zip                        *
Echo *  Usage: Source Folder, Destination Drive Letter      *
Echo *  Source Folder will be Zipped to Destination\Backups *
Echo ********************************************************
Echo off

set year=%date:~-4,4%
set month=%date:~-10,2%
set day=%date:~-7,2%
set hour=%time:~-11,2%
set hour=%hour: =0%
set min=%time:~-8,2%

SET /P src=Source Folder to Backup: 
SET source=%src%\*
call :file_name_from_path nam %src%
SET /P destination=Backup Drive Letter:
set zipfilename=%nam%.%year%.%month%.%day%.%hour%%min%.zip
set dest="%destination%:\Backups\%zipfilename%"


set AppExePath="%ProgramFiles(x86)%\7-Zip\7z.exe"
if not exist %AppExePath% set AppExePath="%ProgramFiles%\7-Zip\7z.exe"

if not exist %AppExePath% goto notInstalled

echo Backing up %source% to %dest%

%AppExePath% a -r -tzip %dest% %source%

echo %source% backed up to %dest% is complete!

TIMEOUT 5

exit;

:file_name_from_path <resultVar> <pathVar>
(
    set "%~1=%~nx2"
    exit /b
)


:notInstalled

echo Can not find 7-Zip, please install it from:
echo  http://7-zip.org/

:end
PAUSE

Answer 5

In case the accepted answer by Wadih didn't work for you, try echo %CD%

Answer 6

I had same problem in my loop where i wanted to extract zip files in the same directory and then delete the zip file. The problem was that 7z requires the output folder, so i had to obtain the folder path of each file. Here is my solution:

FOR /F "usebackq tokens=1" %%i IN (`DIR /S/B *.zip` ) DO (
  7z.exe x %%i -aoa -o%%i\..
) 

%%i was a full filename path and %ii\.. simply returns the parent folder.

hope it helps.

Answer 7

In case anyone wants an alternative method...

If it is the last subdirectory in the path, you can use this one-liner:

cd "c:\directory\subdirectory\filename.exe\..\.." && dir /ad /b /s

This would return the following:

c:\directory\subdirectory

The .... drops back to the previous directory. /ad shows only directories /b is a bare format listing /s includes all subdirectories. This is used to get the full path of the directory to print.

Answer 8

The accepted answer is helpful, but it isn't immediately obvious how to retrieve a filename from a path if you are NOT using passed in values. I was able to work this out from this thread, but in case others aren't so lucky, here is how it is done:

@echo off
setlocal enabledelayedexpansion enableextensions

set myPath=C:\Somewhere\Somewhere\SomeFile.txt
call :file_name_from_path result !myPath!
echo %result%
goto :eof

:file_name_from_path <resultVar> <pathVar>
(
    set "%~1=%~nx2"
    exit /b
)

:eof
endlocal

Now the :file_name_from_path function can be used anywhere to retrieve the value, not just for passed in arguments. This can be extremely helpful if the arguments can be passed into the file in an indeterminate order or the path isn't passed into the file at all.

Answer 9

In order to assign these to variables, be sure not to add spaces in front or after the equals sign:

set filepath=%~dp1
set filename=%~nx1

Then you should have no issues.