CODEWITHSUNDEEP
c
Mahmoud Hamada
Mahmoud Hamada

Reputation: 1

i got error in this code expected ';', ',' or ')' before numeric constant|

I want to know why did i get this error? "D:\C Programming\C training projects\bubblePointer\main.c|6|error: expected ';', ',' or ')' before numeric constant". I need to understand why< however the code in "C how to program" pass size of array also

#include <stdio.h>
#include <stdlib.h>
#define size 10

//prototype
void bubble(unsigned int a[],const size_t size);
void swap(unsigned int *ptr1,unsigned int *ptr2);

int main()
{

unsigned int response[size] =
{6, 7, 8, 9, 8, 7, 8, 9, 8, 9};
 bubble(response,size);

    return 0;
}
void bubble(unsigned int a[],const size_t  size)
{
    int pass;
    for(pass=0;pass<size-1;pass++)
    {
        int j;
        for(j=0;j<size-1;j++)
        {
    // swap adjacent elements if they’re out of order
            if(a[j]>a[j+1])
            {
            swap(&a[j],&a[j+1]);
            }
        }
    }
    // output sorted array
 size_t i;
 for ( i = 0; i < size; ++i)
    {
 printf("%4d", a[i]);
  }

}

void swap(unsigned int *ptr1,unsigned int *ptr2)
{

        unsigned int hold;
        hold=*ptr1;
        *ptr1=*ptr2;
        *ptr2=hold;

}

Upvotes: 0

Views: 172

Answers (1)

Adrian Mole
Adrian Mole

Reputation: 51825

Your #define size 10 instructs the pre-processor to replace all instances of the token size with 10. Thus, your declaration (and definition) of the function:

void bubble(unsigned int a[],const size_t size);

will be converted to:

void bubble(unsigned int a[],const size_t 10);

before the actual compilation process gets to work.

Can you see what's wrong with that second definition? Of course, you can't use 10 as the name of a parameter.

What you need to do is: either rename that parameter (say, size_arg) or (depending on your reason for defining the size macro in the first place) remove that parameter from the function and just use that predefinition in the function's code.

Upvotes: 3

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