Reputation: 555
Currently what I execute the job, then 3 processes will be started on the same time.
def someFunctionJob(x,y,**kwargs):
..... Code which will do some job
def manager(x,values):
y = uuid.uuid4().hex
pr = Process(target=someFunctionJob,args=(x,y,),kwargs=values)
pr.start()
def main(x,values,settings):
for i in settings:
if xyz in ["abc"]:
manager(x,values)
elif lender in ["abc1"]:
manager(lender,product)
elif lender in ["abc2"]:
manager(x,values)
What I need is that it will be managed by queue:
E.G. if workers = 2
The execution will be like this:
process 1
process 2
waiting till any of the processes will be finished
process 3
Upvotes: 1
Views: 60
Reputation: 1456
processes=[]
for _ in range(2):
p = Process(target=something )
p.start()
processes.append(p)
for process in processes:
process.join()
p = Process(target=something )
p.start()
What this code does is it executes 2 processes above then waits them finish and run another separate process.
Upvotes: 1