CODEWITHSUNDEEP
sqloracle-databaseregexp-substr
tan
tan

Reputation: 19

oracle sql extract the word before a specific word

Using oracle, how to get a specific word before a word. i got a sample script that i found here but its in reverse(it gets the word after a specific word which is the CITY)

select regexp_substr ('TEXAS CITY CALIFORNIA', 'CITY[[:space:]]([[:alpha:]]+)', 1, 1, NULL, 1 test from dual;

result: CALIFORNIA

what i want is to get is texas, but i need a dynamic script.

Upvotes: 0

Views: 1160

Answers (3)

Popeye
Popeye

Reputation: 35900

Efficient way to achieve the desired result is to use substr and instr as follows:

substr('TEXAS CITY, CALIFORNIA',1, instr('TEXAS CITY, CALIFORNIA',' CITY'))

db<>fiddle

Upvotes: 1

Tyler Morris
Tyler Morris

Reputation: 21

Assuming that "CITY" won't always be the second word, this will get you only the word immediately preceding "CITY" for any string.

select regexp_substr (regexp_substr('TEXAS CITY, CALIFORNIA', '([[:alpha:]]+)[[:space:]]CITY', 1), '^[^ ]+', 1)test from   dual

For more information, check out how regex works in Oracle SQL.

https://docs.oracle.com/cd/B12037_01/appdev.101/b10795/adfns_re.htm

Upvotes: 0

Kazi Mohammad Ali Nur Romel
Kazi Mohammad Ali Nur Romel

Reputation: 15893

You can extract first word from any sentence with below code:

select regexp_substr ('TEXAS CITY, CALIFORNIA', '^[^ ]+',1 )test from dual;

Upvotes: 0

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