Reputation: 71
I have an HTML table and I need to define a function that should grab the data from the table and build an array of objects that contains table data. Outside the function I have to declare a variable and assign the returned value from the function.
Thanks in advance.
HTML
<table>
<thead>
<tr>
<th>Name</th>
<th>Rating</th>
<th>Review</th>
</tr>
</thead>
<tbody>
<tr>
<td>Bob</td>
<td>5/5</td>
<td>This product is so good, I bought 5 more!</td>
</tr>
<tr>
<td>Jane</td>
<td>4/5</td>
<td>Good value for the price.</td>
</tr>
<tr>
<td>David</td>
<td>1/5</td>
<td>Arrived broken :(</td>
</tr>
<tr>
<td>Fiona</td>
<td>5/5</td>
<td>I love it!</td>
</tr>
<tr>
<td>Michael</td>
<td>3/5</td>
<td>Doesn't live up to expectations.</td>
</tr>
</tbody>
</table>
JS
function buildTableData() {
let tbody = document.getElementsByTagName("tbody")[0];
let rows = tbody.children;
let people = [];
for (let row of rows) {
let person = {};
let cells = row.children;
person.rating = cells[0].textContent;
person.review = cells[1].textContent;
person.favoriteFood = cells[2].textContent;
people.push(person);
return people;
}
let data = people;
console.log(data);
}
Upvotes: 1
Views: 1443
Reputation: 68933
You can try using querySelectorAll()
and map()
like the following way:
function buildTableData() {
let rows = document.querySelectorAll('tbody tr');
let data = Array.from(rows).map(function(tr){
return {
rating: tr.querySelectorAll('td:nth-child(1)')[0].textContent,
review: tr.querySelectorAll('td:nth-child(2)')[0].textContent,
favoriteFood: tr.querySelectorAll('td:nth-child(3)')[0].textContent
};
});
console.log(data);
}
buildTableData();
<h2>Product reviews</h2>
<table>
<thead>
<tr>
<th>Name</th>
<th>Rating</th>
<th>Review</th>
</tr>
</thead>
<tbody>
<tr>
<td>Bob</td>
<td>5/5</td>
<td>This product is so good, I bought 5 more!</td>
</tr>
<tr>
<td>Jane</td>
<td>4/5</td>
<td>Good value for the price.</td>
</tr>
<tr>
<td>David</td>
<td>1/5</td>
<td>Arrived broken :(</td>
</tr>
<tr>
<td>Fiona</td>
<td>5/5</td>
<td>I love it!</td>
</tr>
<tr>
<td>Michael</td>
<td>3/5</td>
<td>Doesn't live up to expectations.</td>
</tr>
</tbody>
</table>
Upvotes: 1
Reputation: 5004
You can get all the elements by using querySelectorAll('td')
. Then use map to to get only the text of it and return this.
function buildTableData() {
const elements = [...document.querySelectorAll('td')];
return elements.map(x => {
return {content : x.innerHTML}
});
}
console.log(buildTableData());
<body>
<h2>Product reviews</h2>
<table>
<thead>
<tr>
<th>Name</th>
<th>Rating</th>
<th>Review</th>
</tr>
</thead>
<tbody>
<tr>
<td>Bob</td>
<td>5/5</td>
<td>This product is so good, I bought 5 more!</td>
</tr>
<tr>
<td>Jane</td>
<td>4/5</td>
<td>Good value for the price.</td>
</tr>
<tr>
<td>David</td>
<td>1/5</td>
<td>Arrived broken :(</td>
</tr>
<tr>
<td>Fiona</td>
<td>5/5</td>
<td>I love it!</td>
</tr>
<tr>
<td>Michael</td>
<td>3/5</td>
<td>Doesn't live up to expectations.</td>
</tr>
</tbody>
</table>
<script src="https://cdnjs.cloudflare.com/ajax/libs/acorn/7.3.1/acorn.js" integrity="sha512-4GRq4mhgV43mQBgKMBRG9GbneAGisNSqz6DSgiBYsYRTjq2ggGt29Dk5thHHJu38Er7wByX/EZoG+0OcxI5upg==" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/acorn-walk/7.2.0/walk.js" integrity="sha512-j5XDYQOKluxz1i4c7YMMXvjLLw38YFu12kKGYlr2+w/XZLV5Vg2R/VUbhN//K/V6LPKuoOA4pfcPXB5NgV7Gwg==" crossorigin="anonymous"></script>
<script src="index.js"></script>
</body>
Upvotes: 1
Reputation: 1608
You want a loop, and each review to be an object that is appended to an array of reviews is what I'm assuming
var reviews = [];
var tbody = document.querySelectorAll("tbody")[0];
var TRs = tbody.querySelectorAll("tr");
for (var a = 0; a < TRs.length; a++) {
var TDs = TRs[a].querySelectorAll("td");
var review = {
name: "",
rating: "",
review: ""
};
//These assume the order of your table columns don't change
review.name = TDs[0].innerHTML;
review.rating = TDs[1].innerHTML;
review.review = TDs[2].innerHTML;
reviews.push(review);
}
Your reviews
array should have everything in there just as you wanted. I assumed the third column was "review" instead of "favorite food"
Upvotes: 0