CODEWITHSUNDEEP
pythonunicodebraille
Joshua66252
Joshua66252

Reputation: 3

Trying To Create Table To Braille In Python

I've Been Trying To Create A System Which Turns A Table Of 1's And 0's To A Braille Character But It Keeps Giving Me This Error

File "brail.py", line 16 stringToWrite=u"\u"+brail([1,1,1,0,0,0,1,1]) ^ SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-1: truncated \uXXXX escape

My Current Code Is

def brail(brailList):
    if len(brailList) == 8:
        brailList.reverse()
        brailHelperList=[0x80,0x40,0x20,0x10,0x8,0x4,0x2,0x1]
        brailNum=0x0
        for num in range(len(brailList)):
            if brailList[num] == 1:
                brailNum+=brailHelperList[num]
        stringToReturn="28"+str(hex(brailNum))[2:len(str(hex(brailNum)))]
        return stringToReturn
    else:
        return "String Needs To Be 8 In Length"

fileWrite=open('Write.txt','w',encoding="utf-8")
stringToWrite=u"\u"+brail([1,1,1,0,0,0,1,1])
fileWrite.write(stringToWrite)
fileWrite.close()

It Works When I Do fileWrite.write(u"\u28c7") But When I Do A Function Which Should Return That Exact Same Thing It Errors.

Image Of Code Just In Case

Upvotes: 0

Views: 738

Answers (3)

Joshua66252
Joshua66252

Reputation: 3

def braille(brailleString):
    brailleList = []
    brailleList[:0]=brailleString
    if len(brailleList) > 8:
        brailleList=brailleList[0:8]
    if len(brailleList) < 8:
        while len(brailleList) < 8:
            brailleList.append('0')
    brailleList1=[
    int(brailleList[0]),
    int(brailleList[1]),
    int(brailleList[2]),
    int(brailleList[4]),
    int(brailleList[5]),
    int(brailleList[6]),
    int(brailleList[3]),
    int(brailleList[7]),
    ]
    brailleList1.reverse()
    brailleHelperList=[128,64,32,16,8,4,2,1]
    brailleNum=0
    for num in range(len(brailleList1)):
        if brailleList1[num] == 1:
            brailleNum+=brailleHelperList[num]
    brailleStart = 10240
    return chr(brailleStart+brailleNum)
fileWrite=open('Write.txt','w',encoding="utf-16")
fileWrite.write(braille('11111111'))
fileWrite.close()

# Think Of The Braille Functions String Like It Has A Seperator In The Middle And The 1s And 0s Are Going Vertically

Upvotes: -1

mhawke
mhawke

Reputation: 87134

\u is the unicode escape sequence for Python literal strings. A 4 hex digit unicode code point is expected to follow the escape sequence. It is a syntax error if the code point is missing or is too short.

>>> '\u28c7'
'⣇'

>>> '\u'
  File "<stdin>", line 1
    '\u'
        ^
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-1: truncated \uXXXX escape

If you are using Python 3 then the u string prefix is not required as strings are stored as unicode internally. The u prefix was maintained for compatibility with Python 2 code.

That's the cause of the exception, however, you don't need to construct the unicode code point like that. You can use the ord() and chr() functions:

    from unicodedata import lookup
    braille_start = ord(lookup('BRAILLE PATTERN BLANK'))
    return chr(braille_start + brailNum)

Upvotes: 1

goalie1998
goalie1998

Reputation: 1442

You can rewrite

stringToWrite=u"\u"+brail([1,1,1,0,0,0,1,1])

as

stringToWrite="\\u{0}".format(brail([1, 1, 1, 0, 0, 0, 1, 1]))

All strings are unicode in Python 3, so you don't need the leading "u".

Upvotes: 0

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