CODEWITHSUNDEEP
pythonlist
pylearner
pylearner

Reputation: 1460

Trying to get the length of lists from a list and their count based on length of each list

am trying to get the length of list and their count in a given list

for ex:

l1 = [['a', 'b', 'c'],['c', 'd', 'f'],['g', 'h', 't', 'j']]

output:

a_3 = 2
b_4  = 1

Upvotes: 0

Views: 49

Answers (4)

David
David

Reputation: 8318

Another solution using collections.Counter is:

from collections import Counter
l = [['a', 'b', 'c'], ['c', 'd', 'f'], ['g', 'h', 't', 'j']]
counts = Counter(map(len,l))

map will iterate over the nested lists inside l and apply len to each of them, then Counter will save each returned length as key and the amount of repetition of that length.

Upvotes: 4

rhurwitz
rhurwitz

Reputation: 2767

You can streamline things a bit more by using a defaultdict

from collections import defaultdict

list_of_lists = [['a', 'b', 'c'],['c', 'd', 'f'],['g', 'h', 't', 'j']]
list_counter = defaultdict(int)

for one_list in list_of_lists:
    list_counter[len(one_list)] += 1


print(list_counter)

defaultdict(<class 'int'>, {3: 2, 4: 1})

Upvotes: 0

Krishna Chaurasia
Krishna Chaurasia

Reputation: 9600

You can iterate over the list elements and create a dictionary with counts as:

l1 = [['a', 'b', 'c'], ['c', 'd', 'f'], ['g', 'h', 't', 'j']]
res = dict()
for k in l1:
    if len(k) not in res:
        res[len(k)] = 1
    else:
        res[len(k)] += 1
print(res)

Output:

{3: 2, 4: 1}

Upvotes: 2

pylearner
pylearner

Reputation: 1460

a_4 = 0
a_3 = 0
for i in mylist:
    if len(i) == 4:
        a_4 += 1
    else:
        a_3 += 1

Upvotes: 0

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