CODEWITHSUNDEEP
pythonfor-looprectangles
Akachukwu Mba
Akachukwu Mba

Reputation: 7

For loops program to print out a rectangle

I have a problem writing a program with for loops. I am not sure how to go about it but I first of all looped through a string containing a number. And now I need to replicate a string '#' with the individual numbers within that number e.g. I want to replicate the string '#' by replicating it with 2 from '274878'. This is my code so far:

bars_string = input('Enter bars string:\n ')
print('+---------+')
for element in bars_string:
  pass

This is my expected output for a given number string:

Enter bars string:
2378945
+---------+
|##       |
|###      |
|#######  |
|######## |
|#########|
|####     |
|#####    |
+---------+

Upvotes: 1

Views: 189

Answers (3)

Alain T.
Alain T.

Reputation: 42143

You can use format strings:

barString = "2378945"

print("+---------+")
print(*(f"|{'#'*int(n):9}|" for n in barString),sep="\n")
print("+---------+")


+---------+
|##       |
|###      |
|#######  |
|######## |
|#########|
|####     |
|#####    |
+---------+

Upvotes: 1

Pablo C
Pablo C

Reputation: 4761

You can do it this way:

bars_string = input('Enter bars string:\n ')
digits = list(map(int, bars_string))
max_digit = max(digits)

print("+" + "-"*max_digit + "+")
for digit in digits:
  print("|" + "#"*digit + " "*(max_digit - digit) + "|")

print("+" + "-"*max_digit + "+")

Upvotes: 2

NOT A GIF
NOT A GIF

Reputation: 79

To do this, you need to times the # with the element in integer form. And in python, you can literally times strings with a number! Here's the code:

bars_string = input('Enter bars string:\n ')
#2378945
for element in bars_string:
  print('#'*int(element))

Upvotes: 0

Related Questions