Reputation: 196791
How do I divide two integers to get a double?
Upvotes: 381
Views: 360831
Reputation: 320
In the comment to the accepted answer there is a distinction made which seems to be worth highlighting in a separate answer.
The correct code:
double num3 = (double)num1/(double)num2;
is not the same as casting the result of integer division:
double num3 = (double)(num1/num2);
Given num1 = 7 and num2 = 12:
The correct code will result in num3 = 0.5833333
Casting the result of integer division will result in num3 = 0.00
Upvotes: 2
Reputation: 375
The easiest way to do that is adding decimal places to your integer.
Ex.:
var v1 = 1 / 30 //the result is 0
var v2 = 1.00 / 30.00 //the result is 0.033333333333333333
Upvotes: 1
Reputation: 1
I have went through most of the answers and im pretty sure that it's unachievable. Whatever you try to divide two int into double or float is not gonna happen. But you have tons of methods to make the calculation happen, just cast them into float or double before the calculation will be fine.
Upvotes: 0
Reputation: 10083
Complementing the @NoahD's answer
To have a greater precision you can cast to decimal:
(decimal)100/863
//0.1158748551564310544611819235
Or:
Decimal.Divide(100, 863)
//0.1158748551564310544611819235
Double are represented allocating 64 bits while decimal uses 128
(double)100/863
//0.11587485515643106
For more details about the floating point representation in binary and its precision take a look at this article from Jon Skeet where he talks about floats
and doubles
and this one where he talks about decimals
.
Upvotes: 51
Reputation: 1491
var firstNumber=5000,
secondeNumber=37;
var decimalResult = decimal.Divide(firstNumber,secondeNumber);
Console.WriteLine(decimalResult );
Upvotes: 4
Reputation: 8302
You want to cast the numbers:
double num3 = (double)num1/(double)num2;
Note: If any of the arguments in C# is a double
, a double
divide is used which results in a double
. So, the following would work too:
double num3 = (double)num1/num2;
For more information see:
Upvotes: 585
Reputation: 308520
Convert one of them to a double first. This form works in many languages:
real_result = (int_numerator + 0.0) / int_denominator
Upvotes: 9