Reputation: 1110
I like to separate soms function and var from a enum and thought this was a way. (Just sample code) This results in a compile error "Type 'Self' has no member 'allCases'"
public protocol EnumFunctions: Hashable {
static var numOfCases: Self { get }
}
public extension EnumFunctions {
static var numOfCases: Self {
return self.allCases.count
}
}
my Enum Cooking Timer
public struct Cook_Time {
// struct naming for the dump command like
// dump(Cook_Time(), name: Cook_Time().structname)
let structname : String = "Cook_Time"
let a = "a"
let allValues = PFTime.allValues
public enum PFTime : String , CaseIterable, EnumFunctions {
case t1m = "1mim"
case t3m = "3min"
case t5m = "5min"
case t10m = "10min"
....
static let allValues = PFTimer.allCases.map { $0.rawValue }
}
}
How can I fix this? what is my false mind setting about this? I do need Self instead of self, rigth?
Also if I make an extension for PFTime, in a separated file, why does I get the error "Cannot find type 'PFTime' in scope"?
Upvotes: 1
Views: 789
Reputation: 8327
In order to access allCases
property of CaseIterable
protocol, you need to change your EnumFunctions
protocol to something like this:
public protocol EnumFunctions: Hashable, CaseIterable {
static var numOfCases: Int { get }
}
public extension EnumFunctions {
static var numOfCases: Int {
return allCases.count
}
}
Also you can create an extension to PFTime
just by adding Cook_Time.
as prefix because PFTime
is placed inside Cook_Time
struct:
extension Cook_Time.PFTime {
}
Upvotes: 1