Reputation: 941
I am making a bash backup script and I want to implement a functionality that checks if the files from a directory are already contained in another directory, if they are not I want to output the name of these files
#!/bin/bash
TARGET_DIR=$1
INITIAL_DIR=$2
TARG_ls=$(ls -A $1)
INIT_ls=$(ls -A $2)
if [[ "$(ls -A $2)" ]]; then
if [[ ! -n "$(${TARG_ls} | grep ${INIT_ls})" ]]; then
echo All files in ${INITIAL_DIR} have backups for today in ${TARGET_DIR}
exit 0
else
#code for listing the missing files
fi
else
echo Error!! ${INITIAL_DIR} has no files
exit 1
fi
I have thought about storing the ls output of both directories inside strings and comparing them, as it is shown in the code, but in the event where I have to list the files from INITIAL_DIR that are missing in TARGET_DIR, I just don't know how to proceed.
I tried using the diff
command comparing the two directories but that takes into account the preexisting files of TARGET_DIR.
In the above code if [[ "$(ls -A $2)" ]];
checks if the CURRENT_DIR contains any files and if [[ ! -n "$(${TARG_ls} | grep ${INIT_ls})" ]];
checks if the target directory contains all the initial directory files.
Anyone have a suggestion, hint?
Upvotes: 0
Views: 394
Reputation: 977
rsync has a --dry-run switch that will show you what files have changed between 2 directories. Before doing rsync copies of my home directory I preview the changes this way to see if there could be evidence of mass mal encryption or corruption before proceeding.
Upvotes: 0
Reputation: 67477
you can use comm
command
$ comm <(ls -A a) <(ls -A b)
will give you files in a only, both in a and b, and in only b in three columns. To get the list of files in a only for example
$ comm -23 <(ls -A a) <(ls -A b)
Upvotes: 1