CODEWITHSUNDEEP
pythonlistnested
Double AA
Double AA

Reputation: 5969

Turning a list into nested lists in python

Possible Duplicate:
How can I turn a list into an array in python?

How can I turn a list such as:

data_list = [0,1,2,3,4,5,6,7,8]

into a list of lists such as:

new_list = [ [0,1,2] , [3,4,5] , [6,7,8] ]

ie I want to group ordered elements in a list and keep them in an ordered list. How can I do this?

Upvotes: 42

Views: 62737

Answers (9)

Sithembiso McGarethson
Sithembiso McGarethson

Reputation: 1

Here is a generalized solution

import math

data_list = [0,1,2,3,4,5,6,7,8]
batch_size=3

n_batches=math.ceil(len(data_list)/batch_size)

[data_list[x*batch_size:min(x*batch_size+batch_size,len(data_list))] 
    for x in range(n_batches)]

It works even if the last sublist is not the same size as the rest (<batch_size)

Upvotes: 0

Sindhukumari P
Sindhukumari P

Reputation: 350

The below one is more optimized and quite straightforward.

data_list = [0,1,2,3,4,5,6,7,8]
result =[]
i=0
while i <(len(data_list)-2):
    result.append(data_list[i:i+3])
    i+=3
print(result)

**output**

[[0, 1, 2], [3, 4, 5], [6, 7, 8]]

Upvotes: 0

user12446118
user12446118

Reputation:

The following function expands the original context to include any desired list of lists structure:

def gen_list_of_lists(original_list, new_structure):
    assert len(original_list) == sum(new_structure), \
    "The number of elements in the original list and desired structure don't match"
        
    list_of_lists = [[original_list[i + sum(new_structure[:j])] for i in range(new_structure[j])] \
                     for j in range(len(new_structure))]
        
    return list_of_lists

Using the above:

data_list = [0,1,2,3,4,5,6,7,8]
    
new_list = gen_list_of_lists(original_list=data_list, new_structure=[3,3,3])
# The original desired outcome of [[0,1,2], [3,4,5], [6,7,8]]

new_list = gen_list_of_lists(original_list=data_list, new_structure=[2,3,3,1])
# [[0, 1], [2, 3, 4], [5, 6, 7], [8]]

Upvotes: 1

Cœur
Cœur

Reputation: 38667

Based on the answer from Fred Foo, if you're already using numpy, you may use reshape to get a 2d array without copying the data:

import numpy
new_list = numpy.array(data_list).reshape(-1, 3)

Upvotes: 5

jsbueno
jsbueno

Reputation: 110218

This groups each 3 elements in the order they appear:

new_list = [data_list[i:i+3] for i in range(0, len(data_list), 3)]

Give us a better example if it is not what you want.

Upvotes: 90

ba__friend
ba__friend

Reputation: 5903

new_list = [data_list[x:x+3] for x in range(0, len(data_list) - 2, 3)]

List comprehensions for the win :)

Upvotes: 4

Graham
Graham

Reputation: 1084

This assumes that data_list has a length that is a multiple of three

i=0
new_list=[]
while i<len(data_list):
  new_list.append(data_list[i:i+3])
  i+=3

Upvotes: 23

Hyperboreus
Hyperboreus

Reputation: 32429

Something like:

map (lambda x: data_list[3*x:(x+1)*3], range (3))

Upvotes: 8

Manny D
Manny D

Reputation: 20714

Do you have any sort of selection criteria from your original list?

Python does allow you to do this:

new_list = []
new_list.append(data_list[:3])
new_list.append(data_list[3:6])
new_list.append(data_list[6:])

print new_list
# Output:  [ [0,1,2] , [3,4,5] , [6,7,8] ]

Upvotes: -1

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