CODEWITHSUNDEEP
c++syntax
Young Lee
Young Lee

Reputation: 1

Error: invalid type argument of unary '*' (have 'int') on my code

When I run this code, I receive the following error:

invalid type argument of unary '*' (have 'int')

How can I clear this up?

#include <iostream>
#include <string>
#include <typeinfo>

using namespace std;

void multiplyFive (int &x, int y, int *z){
    int d = 5 * x;
    int e = 5 * y;
    int f = 5 * *z;
    cout << d << " " << e << " " << f << endl;
}

int main() {
    int a = 2;
    int *b = &a;
    int &c = *b;

    multiplyFive (a, b, *c);
    
    return EXIT_SUCCESS;
}

Upvotes: 0

Views: 845

Answers (1)

463035818_is_not_an_ai
463035818_is_not_an_ai

Reputation: 123084

Clangs error message is a bit more helpful:

<source>:19:21: error: indirection requires pointer operand ('int' invalid)
multiplyFive (a, b, *c);
                    ^~

c is a reference to an int not a pointer, you cannot dereference it via *.

It seems like you mixed up 2nd and 3rd parameters to multiplyFive, because the next error you will receive is that b is a int* but multiplyFive expects a int in its place.

Upvotes: 1

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