Reputation: 41
I don't know how to crawl the title of the page,below is my code(it's simple),but I have no idea where is wrong, if you have any idea please let me know,thank you.
from selenium import webdriver
url="https://sukebei.nyaa.si/?s=seeders&o=desc&p=1"
driver_path = "C:\\webdriver\\chromedriver.exe"
option = webdriver.ChromeOptions()
driver = webdriver.Chrome(driver_path, options=option)
driver.implicitly_wait(10)
driver.get(url)
print(driver.find_element_by_xpath("/html/head/title").text)
Upvotes: 1
Views: 307
Reputation: 193078
To crawl the title of the page you have to induce WebDriverWait for the visibility_of_element_located()
for the <table>
with torrent-list and you can use either of the following Locator Strategies:
Using CSS_SELECTOR
:
driver.get('https://sukebei.nyaa.si/?s=seeders&o=desc&p=1')
WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "table.torrent-list")))
print(driver.title)
Using XPATH
:
driver.get('https://sukebei.nyaa.si/?s=seeders&o=desc&p=1')
WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//table[contains(@class, 'torrent-list')]")))
print(driver.title)
Console Output:
Browse :: Sukebei
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Upvotes: 2
Reputation: 281
from selenium import webdriver
url="https://sukebei.nyaa.si/?s=seeders&o=desc&p=1"
driver_path = "C:\\webdriver\\chromedriver.exe"
option = webdriver.ChromeOptions()
driver = webdriver.Chrome(driver_path, options=option)
driver.implicitly_wait(10)
driver.get(url)
print(driver.title)
Upvotes: 1