Reputation: 361
I declare a class variable for a StatefulWidget - in the code below it's someString
.
Is it possible to use this variable in the build(…)
-method without declaring it as static?
class MyClass extends StatefulWidget {
String someString;
MyClass() {
this.someString = "foo";
}
@override
_MyClassState createState() => _MyClassState();
}
class _MyClassState extends State<MyClass> {
_MyClassState();
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text("someString - how to access it here?!"),
// title: Text(someString), is not possible, obviously
),
);
}
}
Thanks in advance for help!
Upvotes: 3
Views: 1741
Reputation: 8383
Attention: MyClass
should be immutable.
someString
will never changeKeep it inside MyClass
but define it as final.
class MyClass extends StatefulWidget {
final String someString;
const MyClass({Key key, this.someString = 'foo'}) : super(key: key);
@override
_MyClassState createState() => _MyClassState();
}
Then, inside the State, you can use it as widget.someString
:
class _MyClassState extends State<MyClass> {
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(title: Text('${widget.someString} is accessed here?!')),
);
}
}
someString
will changeIt should be defined in the state.
class MyClass extends StatefulWidget {
final String initialValue;
const MyClass({Key key, this.initialValue = 'foo'}) : super(key: key);
@override
_MyClassState createState() => _MyClassState();
}
class _MyClassState extends State<MyClass> {
String someString;
@override
void initState() {
someString = widget.initialValue;
super.initState();
}
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(title: Text('$someString is accessed here?!')),
body: Center(
child: OutlinedButton(
onPressed: () => setState(() => someString = 'NEW Value'),
child: Text('Update value'),
),
),
);
}
}
Upvotes: 7