Reputation: 11
I'm new to SQL and this website so apologies if anything is unclear.
Basically, I got two separate tables:
Table A:
CustomerID | PromoStart | PromoEnd
1 | 2020-05-01 | 2020-05-30
2 | 2020-06-01 | 2020-07-30
3 | 2020-07-01 | 2020-10-15
Table B:
CustomerID | Date | Payment |
1 | 2020-02-15 | 5000 |
1 | 2020-05-04 | 200 |
1 | 2020-05-28 | 100 |
1 | 2020-06-05 | 1000 |
2 | 2020-06-10 | 20 |
2 | 2020-07-25 | 500 |
2 | 2020-08-02 | 1000 |
3 | 2020-09-05 | 580 |
3 | 2020-12-01 | 20 |
What I want is to get the sum of all payments that fall between PromoStart
and PromoEnd
for each customer.
so the desired result would be :
CustomerID | TotalPayments
1 | 300
2 | 520
3 | 580
I guess this would involve an inner (left?) join and a where clause however I just can't figure it out.
Upvotes: 1
Views: 852
Reputation: 12000
I hope I didn't overlook something important but it seems to me simple join on range matching condition should be sufficient:
with a (CustomerID , PromoStart , PromoEnd) as (values
(1 , date '2020-05-01' , date '2020-05-30'),
(2 , date '2020-06-01' , date '2020-07-30'),
(3 , date '2020-07-01' , date '2020-10-15')
), b (CustomerID , d , Payment ) as (values
(1 , date '2020-02-15' , 5000 ),
(1 , date '2020-05-04' , 200 ),
(1 , date '2020-05-28' , 100 ),
(1 , date '2020-06-05' , 1000 ),
(2 , date '2020-06-10' , 20 ),
(2 , date '2020-07-25' , 500 ),
(2 , date '2020-08-02' , 1000 ),
(3 , date '2020-09-05' , 580 ),
(3 , date '2020-12-01' , 20 )
)
select a.CustomerID, sum(b.Payment)
from a
join b on a.CustomerID = b.CustomerID and b.d between a.PromoStart and PromoEnd
group by a.CustomerID
Upvotes: 0
Reputation: 1269633
You can use a correlated subquery or join
with aggregation. The correlated subquery looks like:
select a.*,
(select sum(b.payment)
from b
where b.customerid = a.customerid and
b.date >= a.promostart and
b.date <= a.promoend
) as totalpayments
from a;
You don't mention your database, but this can take advantage of an index on b(customerid, date, payment)
. By avoiding the outer aggregation, this would often have better performance than an alternative using group by
.
Upvotes: 1
Reputation: 656471
A LATERAL
join would do it:
SELECT a.customer_id, b.total_payments
FROM table_a a
LEFT JOIN LATERAL (
SELECT sum(payment) AS total_payments
FROM table_b
WHERE customer_id = a.customer_id
AND date BETWEEN a.promo_start AND a.promo_end
) b ON true;
This assumes inclusive lower and upper bounds, and that you want to include all rows from table_a
, even without any payments in table_b
.
Upvotes: 1