CODEWITHSUNDEEP
c
Advait Dandekar
Advait Dandekar

Reputation: 45

I'm writing this program to find double digit odd numbers in a single number and I'm stuck

I'm writing this program to find double digit odd numbers in a single number and I'm stuck.

For ex- In the number 56789 there are two double digit odd numbers: 67 & 89. I've written the code for this:

#include<stdio.h>
#include<conio.h>
int main()
{
    int num,rem=0;
    int odd=0;
    printf("Enter a number: ");
    scanf("%d",&num);
    while(num>0)
    {
        rem=(num%100);
        printf("%d\n",rem);
        if(rem%2!=0)
        {
            odd++;
        }
        num=num/10;
        
    }
    printf("Odd digits count is: %d",odd);
    return 0;
}

Here's my problem:

Input: 56789, output: "89\n78\n67\n56\n5\nOdd digit count is: 3"

Expected Output: 67 89 Total number of odd digit numbers: 2

Upvotes: 2

Views: 690

Answers (1)

Werner Henze
Werner Henze

Reputation: 16726

while(num>0) allows single and double digit numbers.
while(num>=10) allows only double digit numbers.

Upvotes: 2

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