msapere
Reputation: 191
why does AND in parenthesis evaluate differently than without?
In C++, 4&1 == 0, and 1&1 == 1. However, 4&1 != 1&1 evaluates to 0, instead of 1, yet (4&1) != (1&1) evaluates to 1 as expected. Why is this?
Upvotes: 5
Views: 125
Answers (1)
Brian61354270
Reputation: 14423
The relational operator != has a higher precedence than bitwise AND &.
Thus the expression
4 & 1 != 1 & 1
will be parsed as
4 & (1 != 1) & 1
Upvotes: 6
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