CODEWITHSUNDEEP
pythondictionary
Rahul Sharma
Rahul Sharma

Reputation: 2495

create a dictionary from variables of another dictionary

I have a dictionary like the following:

{'invoice_date': '2021-02-12T15:48:52+05:30', 
'no_of_bill_files': '3', 
'amount': '12', 'gst': '12',
'bill0': 123, 'bill1': 456, 'bill2': 789, 'owner': 2}

I want to create a list by name bill which would contain data like this:

bill = [{'document':123},{'document':456},{'document':789}]

the number of dictionary depends upon the number of 'no_of_bill_files' in the above dictionary

How do I do that?

Upvotes: 0

Views: 36

Answers (1)

Sayandip Dutta
Sayandip Dutta

Reputation: 15872

Let's say you first dict name is cond:

>>> cond = {'invoice_date': '2021-02-12T15:48:52+05:30', 
'no_of_bill_files': '3', 
'amount': '12', 'gst': '12',
'bill0': 123, 'bill1': 456, 'bill2': 789, 'owner': 2}

>>> bill = [{'document': cond[f'bill{i}']} for i in range(int(cond['no_of_bill_files']))]
>>> bill
[{'document': 123}, {'document': 456}, {'document': 789}]

Here we use a list comprehension, where the number of iteration is equal to cond['no_of_bill_files'].

>>> cond['no_of_bill_files']
'3'
# Now as it is in string, in order to use it in range
# we will need to convert it to int

Now for range(3), the values after all the iteration will be 0, 1 and 2, we add that to bill using f-string and get the value from cond dict.

>>> for i in range(3):
        print(f'bill{i}')

bill0
bill1
bill2

Upvotes: 1

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