Reputation: 63
How to insert rows for each of the type column? If there is two type, type 1 and type 2, then I need to insert two rows and also need to change the order and id value for whole table.
current status:
CHOICE Table
id choice type order
1 AA 1 1
2 BB 1 2
3 CC 1 3
4 AAA 2 4
5 BBB 2 5
6 CCC 2 6
7 DDD 2 7
Required updated table: Now i wan to insert choice "000" for each type. The updated table will be look like bellow. How can I achieve this?
updated CHOICE Table
id choice type order
1 000 1 1
2 AA 1 2
3 BB 1 3
4 CC 1 4
5 000 2 5
6 AAA 2 6
7 BBB 2 7
8 CCC 2 8
9 DDD 2 9
here, id and order column serialized again.
The actual table is too big, so I cannot insert by edit. Please help for this complex query. I have no clue to solve this.
Upvotes: 0
Views: 33
Reputation: 1269873
Use insert . . . select
to insert the rows:
insert into choice (choice, type)
select distinct '000', type
from choice;
This assumes that id
is automatically assigned (and it will be different from your example).
However, it looks like you want to update the order
as well. For this, I would suggest an update:
update choice c join
(select c2.*,
row_number() over (partition by choice order by (order is null) desc, order) as new_order
from choice c2
) c2
on c.id = c2.id
set c.order = c2.new_order;
As an editorial comment, order
is a very bad choice for a column name because it is a SQL keyword.
Upvotes: 1