CODEWITHSUNDEEP
pythonglob
VioDor
VioDor

Reputation: 13

Glob doesn't return list of files from specified directory

I've found two ways of listing files from a specified directory from other posts here on Stack Overflow but I can't seem to get them working. The first one returns the path and second return the files I'm looking for but also the path. I have tried several ways like renaming the target directory and files but it doesn't seem to do the trick.

The code in question:

import glob

jpgFilenamesList = glob.glob(r"C:\Users\viodo\PycharmProjects\pythonProject")
print(jpgFilenamesList)

mydir = r"C:\Users\viodo\PycharmProjects\pythonProject"

file_list = glob.glob(mydir + "/*.jpg")
print(file_list)

what I get:

['C:\\Users\\viodo\\PycharmProjects\\pythonProject']
['C:\\Users\\viodo\\PycharmProjects\\pythonProject\\dngjknfjkg.jpg', 'C:\\Users\\viodo\\PycharmProjects\\pythonProject\\fjkdnfkl.jpg', 'C:\\Users\\viodo\\PycharmProjects\\pythonProject\\skdklenfkd.jpg']

Solution found in another thread: Python glob multiple filetypes

Some tweaking got it running smoth. Thanks for the help!

Upvotes: 0

Views: 4114

Answers (1)

facelessuser
facelessuser

Reputation: 1734

Glob returns a list of pathnames relative to the root directory. That root directory is assumed to be your current working directory unless the glob pattern specified is an absolute path. In short, because your pattern is an absolute path pattern, the returned files will not be relative, but absolute, including the entire path.

When not using an absolute path pattern, in some cases, you could get just a file name if a file name matches in the current working directory. That file name would of course be relative to the current working directory.

In Python 3.10, you should be able to change the assumed root directory without using an absolute pattern via a new root_dir parameter, but this is not currently available in 3.9 and below: https://docs.python.org/3.10/library/glob.html.

In your case, as mentioned in the comments by othes, os.path.basename should be able to get just the file name if that is what you are after. Alternatively, you could change the current working directory via os.chdir and provide a glob pattern of simply *.jpg and get just the file names relative to the that current working directory, both are reasonable solutions.

Extracting the base name:

mydir = r"C:\Users\viodo\PycharmProjects\pythonProject"
file_list = [os.path.basename(f) for f in glob.glob(mydir + "/*.jpg")]

or returning the files relative to an arbitrary "current working directory":

os.chdir(r"C:\Users\viodo\PycharmProjects\pythonProject")
file_list = glob.glob("*.jpg")

Depending on your requirements, one solution may be better than the other.

Upvotes: 0

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