CODEWITHSUNDEEP
operating-system
LindaK
LindaK

Reputation: 11

Opening file with specific extension in python

I am a self-learned coder and very new to this so please bear with me. I am trying to open a .seis file with the seisop application. the files are located in my documents folder and the excecutable for the application is in C:\Apps\

import os
seis_path = os.getcwd() + "\\seis_Samples"
app_path = "C:\\Apps"
print(seis_path)
print(app_path)
os.system("open -a /appc_path/to/SeisOp.exe /seis_path/to/*.seis")

Upvotes: 0

Views: 51

Answers (1)

LindaK
LindaK

Reputation: 11

in case this may be of interest to anyone, I ended up finding a solution to my problem after much troubleshooting :-D

The issue had to do with the fact that I needed to open the file as a subprocess. The correct syntax to use is the following:

import sys, string, os
import subprocess as sp
APP = "C:\\Apps\\APP.exe"
file = os.getcwd()+"\\seis_Samples\\seisfile"
event = sp.Popen([APP, file])

Upvotes: 1

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