CODEWITHSUNDEEP
pythonlistdictionaryvariables
NewCoder18
NewCoder18

Reputation: 318

How can I pull one item, from a list of dictionary items, using a single key:value pair?

Let's say I have a list of dictionary items:

main_dict = [{'Player': '1', 'position': 'main', 'points': 50},
{'Player': '2', 'position': 'main', 'points': 60},
{'Player': '3', 'position': 'main', 'points': 70},
{'Player': '4', 'position': 'main', 'points': 80},
{'Player': '5', 'position': 'main', 'points': 90}]

I ran some code and got this result: 90

I now want to pull the full dictionary item, from index in the list, using only the value of the points key.

if points == 90:
    new_item = (#find item in main_dict[4])

output: {'Player': '5', 'position': 'main', 'points': 90}

How can I pull the full item out of list, using only the unique value of 90?

Upvotes: 0

Views: 172

Answers (4)

superb rain
superb rain

Reputation: 5531

Yeah I'm gonna assume this is an XY problem and you should just get the item directly, without first finding the points value. For example if you want the player with the most points:

>>> max(main_dict, key=lambda d: d['points'])
{'Player': '5', 'position': 'main', 'points': 90}

Upvotes: 0

Gerges
Gerges

Reputation: 6519

filter built-in should do the trick. If you want to match all items:

new_item = list(filter(lambda x: x['points'] == 90, main_dict))

if you want only the first item which matches:

new_item = next(filter(lambda x: x['points'] == 90, main_dict))

Upvotes: 2

Shraft
Shraft

Reputation: 332

Try this:

main_dict = [{'Player': '1', 'position': 'main', 'points': 50},
{'Player': '2', 'position': 'main', 'points': 60},
{'Player': '3', 'position': 'main', 'points': 70},
{'Player': '4', 'position': 'main', 'points': 80},
{'Player': '5', 'position': 'main', 'points': 90}]

def getDict(i):
    for retDict in main_dict:
        if i == retDict.get('points'):
            return(retDict)

print(getDict(90))

Upvotes: 2

jrhode2
jrhode2

Reputation: 161

You can use filter the list to dicts with 'points': 90 using list comprehension:

[inner_dict for inner_dict in main_dict if inner_dict['points'] == 90]

Upvotes: 1

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