CODEWITHSUNDEEP
python-3.x
Melany
Melany

Reputation: 19

How to update nested dictionary value after comparing key to list item

I want to loop through my_list and comparing the list items to the key in my_dict. How do I update the nested value of '0' for each time an item in the my_list matches the my_dict key?

   my_list = [1102, 4611, 4624, 4634, 1102, 1102, 4611, 1102]
   my_dict = {'1102':{'count':0},'4611':{'count':0},'4624':{'count':0}}
            
   for item in my_list:
      if item in my_dict.keys():
       # count:0 +=1

Upvotes: 1

Views: 41

Answers (1)

some_programmer
some_programmer

Reputation: 3528

You can try this:

my_list = [1102, 4611, 4624, 4634, 1102, 1102, 4611, 1102]
my_dict = {'1102':{'count':0},'4611':{'count':0},'4624':{'count':0}}
            
for item in my_list:
  if str(item) in my_dict.keys():
    my_dict[str(item)]['count'] += 1

print(my_dict)

# {'1102': {'count': 4}, '4611': {'count': 2}, '4624': {'count': 1}}

While using the if statement, don't forget to convert the type of the item from int to str

Upvotes: 1

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