Reputation: 2076
I have several anchor tags in a text,
Input: <a href="http://stackoverflow.com" >Take me to StackOverflow</a>
Output:
http://stackoverflow.com
How can I find all those input strings and convert it to the output string in java, without using a 3rd party API ???
Upvotes: 2
Views: 16326
Reputation: 21
The above example works perfect; if you want to parse an HTML document say instead of concatenated strings, write something like this to compliment the code above.
Existing code above ~ modified to show: HtmlParser.java (HtmlParseDemo.java) above complementing code with HtmlPage.java below. The content of the HtmlPage.properties file is at the bottom of this page.
The main.url property in the HtmlPage.properties file is: main.url=http://www.whatever.com/
That way you can just parse the url that your after. :-) Happy coding :-D
import java.io.Reader;
import java.io.StringReader;
import java.util.ArrayList;
import java.util.List;
import javax.swing.text.MutableAttributeSet;
import javax.swing.text.html.HTML;
import javax.swing.text.html.HTMLEditorKit;
import javax.swing.text.html.parser.ParserDelegator;
public class HtmlParser
{
public static void main(String[] args) throws Exception
{
String html = HtmlPage.getPage();
Reader reader = new StringReader(html);
HTMLEditorKit.Parser parser = new ParserDelegator();
final List<String> links = new ArrayList<String>();
parser.parse(reader, new HTMLEditorKit.ParserCallback()
{
public void handleStartTag(HTML.Tag t, MutableAttributeSet a, int pos)
{
if (t == HTML.Tag.A)
{
Object link = a.getAttribute(HTML.Attribute.HREF);
if (link != null)
{
links.add(String.valueOf(link));
}
}
}
}, true);
reader.close();
// create the header
System.out.println("<html>\n<head>\n <title>Link City</title>\n</head>\n<body>");
// spit out the links and create href
for (String l : links)
{
System.out.print(" <a href=\"" + l + "\">" + l + "</a>\n");
}
// create footer
System.out.println("</body>\n</html>");
}
}
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.StringWriter;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.ResourceBundle;
public class HtmlPage
{
public static String getPage()
{
StringWriter sw = new StringWriter();
ResourceBundle bundle = ResourceBundle.getBundle(HtmlPage.class.getName().toString());
try
{
URL url = new URL(bundle.getString("main.url"));
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("GET");
connection.setDoOutput(true);
InputStream content = (InputStream) connection.getInputStream();
BufferedReader in = new BufferedReader(new InputStreamReader(content));
String line;
while ((line = in.readLine()) != null)
{
sw.append(line).append("\n");
}
} catch (Exception e)
{
e.printStackTrace();
}
return sw.getBuffer().toString();
}
}
For example, this will output links from http://ebay.com.au/ if viewed in a browser. This is a subset, as there are a lot of links
Link City #mainContent http://realestate.ebay.com.au/
Upvotes: 2
Reputation: 29493
public static void main(String[] args) {
String test = "qazwsx<a href=\"http://stackoverflow.com\">Take me to StackOverflow</a>fdgfdhgfd"
+ "<a href=\"http://stackoverflow2.com\">Take me to StackOverflow2</a>dcgdf";
String regex = "<a href=(\"[^\"]*\")[^<]*</a>";
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(test);
System.out.println(m.replaceAll("$1"));
}
NOTE: All Andrzej Doyle's points are valid and if you have more then simple <a href="X">Y</a>
in your input, and you are sure that is parsable HTML, then you are better with HTML parser.
To summarize:
<a>
in comment. (you can treat it as special case) <a>
tag. (again you can treat it as special case)However, if your req is always replace <a href="X">Y</a>
with "X"
without considering the context, then the code i've posted will work.
Upvotes: 5
Reputation: 170288
There are classes in the core API that you can use to get all href
attributes from anchor tags (if present!):
import java.io.*;
import java.util.*;
import javax.swing.text.*;
import javax.swing.text.html.*;
import javax.swing.text.html.parser.*;
public class HtmlParseDemo {
public static void main(String [] args) throws Exception {
String html =
"<a href=\"http://stackoverflow.com\" >Take me to StackOverflow</a> " +
"<!-- " +
"<a href=\"http://ignoreme.com\" >...</a> " +
"--> " +
"<a href=\"http://www.google.com\" >Take me to Google</a> " +
"<a>NOOOoooo!</a> ";
Reader reader = new StringReader(html);
HTMLEditorKit.Parser parser = new ParserDelegator();
final List<String> links = new ArrayList<String>();
parser.parse(reader, new HTMLEditorKit.ParserCallback(){
public void handleStartTag(HTML.Tag t, MutableAttributeSet a, int pos) {
if(t == HTML.Tag.A) {
Object link = a.getAttribute(HTML.Attribute.HREF);
if(link != null) {
links.add(String.valueOf(link));
}
}
}
}, true);
reader.close();
System.out.println(links);
}
}
which will print:
[http://stackoverflow.com, http://www.google.com]
Upvotes: 7
Reputation: 240956
You can use JSoup
String html = "<p>An <a href=\"http://stackoverflow.com\" >Take me to StackOverflow</a> link.</p>";
Document doc = Jsoup.parse(html);
Element link = doc.select("a").first();
String linkHref = link.attr("href"); // "http://stackoverflow.com"
Also See
Upvotes: 5
Reputation: 27604
The most robust way (as has been suggested already) is to use regular expressions (java.util.regexp), if you are required to build this without using 3d party libs.
The alternative is to parse the html as XML, either using a SAX parser to capture and handle each instance of an "a" element or as a DOM Document and then searching it using XPATH (see http://download.oracle.com/javase/6/docs/api/javax/xml/parsers/package-summary.html). This is problematic though, since it requires the HTML page to be fully XML compliant in markup, a very dangerous assumption and not an approach I would recommend since most "real" html pages are not XML compliant.
Still, I would recommend also looking at existing frameworks out there built for this purpose (like JSoup, also mentioned above). No need to reinvent the wheel.
Upvotes: 0