Reputation: 14008
Cosider the simple solution:
sol: solve(b * x - a, x);
a [x = -] b
how can I get the expression part sol: a / b
out of the above result?
solution was offered to me here.
Upvotes: 1
Views: 505
Reputation: 14008
Thanks to Johann Weilharter I found one way to extract the expression:
sol: ev(x, solve(b * x - a, x)[1]);
Of course, if there is more than one solution, you need to change 1
to the specific instance.
Alternatively, as pointed out in the comments of the question, one can also use
sol: rhs(first(solve(b * x - a, x)));
oneliner to do the job.
Upvotes: 1
Reputation: 117
What you need is a symbolic evaluation library. If you are considering a python implementation, you can use SymPy.
import sympy as sym
x = sym.Symbol('x')
b = sym.Symbol('b')
a = sym.Symbol('a')
sol = sym.solve((b * x - a), x)
print(sol)
------
[a/b]
Upvotes: 0