Reputation: 12347
This is my 3rd question about JSON data for jqGrid's subgrid, till now I did not get a single comment. Please somebody help.
my 1st question
and the
2nd one
I am having trouble getting to know the json format to be used by a subgrid in jqGrid. In my 2nd question i asked about the format that I should be using for a particular scenario
for the given image
Is this the proper JSON String?
var myJSONObject = {
"list": [
{
"elementName": "TERM",
"attribute": [
{
"name": "information",
"firstValue": "Required fixes for AIX",
"secondValue": "Required fixes for AIX"
},
{
"name": "name",
"firstValue": "PHCO_34",
"secondValue": "PHCO_34"
},
{
"name": "version",
"firstValue": "1.0",
"secondValue": "2.0"
}
],
"isEqual": false,
"isPrasentinXml1": true,
"isPrasentinXml2": false
},
{
"elementName": "Asian-Core.ASX-JPN-MAN",
"attribute": [
{
"name": "information",
"firstValue": "Man",
"secondValue": "Man"
},
{
"name": "name",
"firstValue": "Asian-Core.ASX-JPN-MAN",
"secondValue": "Asian-Core.ASX-JPN-MAN"
},
{
"name": "version",
"firstValue": "B.11.23",
"secondValue": "B.11.23"
}
],
"isEqual": false,
"isPrasentinXml1": true,
"isPrasentinXml2": true
}
]
};
If yes, my 1st question this is where i reached so far
$('#compareContent').empty();
$('<div id="compareParentDiv" width="100%">')
.html('<table id="list2" cellspacing="0" cellpadding="0"></table>'+
'<div id="gridpager2"></div></div>')
.appendTo('#compareContent');
var grid = jQuery("#list2");
grid.jqGrid({
datastr : myJSONObject,
datatype: 'jsonstring',
colNames:['Name','Result1', 'Result2'],
colModel:[
{name:'elementName',index:'elementName', width:90},
{name:'isPrasentinXml1',index:'isPrasentinXml1', width:100},
{name:'isPrasentinXml2',index:'isPrasentinXml2', width:100},
],
pager : '#gridpager2',
rowNum:10,
scrollOffset:0,
height: 'auto',
autowidth:true,
viewrecords: true,
gridview: true,
jsonReader: { repeatitems : false, root:"list" },
subGrid: true,
/*subGridModel: [{
//subgrid columns names
name: ['Name', 'Version', 'Information'],
//subgrid columns widths
width: [200, 100, 100],
//subrig columns aligns
align: ['left', 'left', 'left']
}]*/
// define the icons in subgrid
subGridOptions: {
"plusicon" : "ui-icon-triangle-1-e",
"minusicon" : "ui-icon-triangle-1-s",
"openicon" : "ui-icon-arrowreturn-1-e",
//expand all rows on load
"expandOnLoad" : true
},
subGridRowExpanded: function(subgrid_id, row_id) {
var subgrid_table_id, pager_id;
subgrid_table_id = subgrid_id+"_t";
pager_id = "p_"+subgrid_table_id;
$("#"+subgrid_id).html("<table id='"+subgrid_table_id+"' class='scroll'></table><div id='"+pager_id+"' class='scroll'></div>");
jQuery("#"+subgrid_table_id).jqGrid({
datastr : myJSONObject,
datatype: 'jsonstring',
colNames: ['Name','Value1','Value2'],
colModel: [
{name:"name",index:"name",width:90},
{name:"firstValue",index:"firstValue",width:100},
{name:"secondValue",index:"secondValue",width:100},
],
rowNum:20,
pager: pager_id,
sortname: 'name',
sortorder: "asc",
height: 'auto',
autowidth:true,
jsonReader: { repeatitems : false, root:"attribute" }
});
jQuery("#"+subgrid_table_id).jqGrid('navGrid',"#"+pager_id,{edit:false,add:false,del:false})
}
});
grid.jqGrid('navGrid','#gridpager2',{add:false,edit:false,del:false});
Any type of suggestions/comments/solutions are welcome. Thanks
My output
Upvotes: 3
Views: 13102
Reputation: 221997
You code has small errors in the declaration of the myJSONObject
variable and the code which create the contain of the div#compareContent
should be fixed to
$('#compareContent').empty();
$('<div id="compareParentDiv" width="100%">'+
'<table id="list2" cellspacing="0" cellpadding="0"></table>'+
'<div id="gridpager2"></div></div>')
.appendTo('#compareContent');
Small other syntax errors are the trailing commas in the colModel
: the comma before ']' should be removed.
Now to your main problem. You should change datastr : myJSONObject
in the subgrid to something like
datastr : myJSONObject.list[0]
then the modified demo will show the data: see here.
One more problem which you has is the absent of ids in your data. You should modify the structure of the data to define the unique ids for very grid row and every subgrid row. You should take in the considerations that ids from the data will be used as id of <tr>
elements and HTML don't permit to have id duplicates on one HTML page.
UPDATED: See here an example of modification of your JSON input and the jqGrid so that ids will be used.
Upvotes: 3
Reputation: 31033
a couple of suggestion that may/maynot workout
when using subgrid select the grid as
var mygrid = jQuery("#mygrid")[0];
replace
var grid = jQuery("#list2");
with
var grid = jQuery("#list2")[0];
Ref: http://www.trirand.com/blog/?page_id=393/help/2-questions-about-jqgrid-subgrid-and-jsonstring
also change your json to a valid
json
{
"list": [
{
"elementName": "TERM",
"attribute": [
{
"name": "information",
"firstValue": "RequiredfixesforAIX",
"secondValue": "RequiredfixesforAIX"
},
{
"name": "name",
"firstValue": "PHCO_34",
"secondValue": "PHCO_34"
},
{
"name": "version",
"firstValue": "1.0",
"secondValue": "2.0"
}
],
"isEqual": false,
"isPrasentinXml1": true,
"isPrasentinXml2": false
}
]
}
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you may find the following link useful
jqGrid with JSON data renders table as empty
Upvotes: 1