CODEWITHSUNDEEP
javastringsplit
Kezza
Kezza

Reputation: 31

Java - How would I split a string into multiple lines depending on an input?

I am new to Java and want to split a message that a user inputs into multiple lines depending on what has been inputted as the maximum length. How would I go about repeating it? Here is what I have so far:

int rem = m - maxlength;
System.out.println(message.substring(0, message.length() - rem));
System.out.println(message.substring(message.length() - rem));

Upvotes: 2

Views: 1570

Answers (5)

RasulOs
RasulOs

Reputation: 109

A little bit of improved @markspace code to get the last words too (matcher does not get the last words because of the end of the line):

public static void main( String[] args ) {
    String s = "I am new to Java and want to split a message that a user inputs into multiple lines depending on what has been inputted as the maximum length. How would I go about repeating it? Here is what I have so far:";

    String regex = ".{1,24}(\\s|$)";

    Matcher m = Pattern.compile(regex).matcher(s);

    while (m.find()) {
        System.out.println(m.group());
    }

Upvotes: 0

Vaibhav Deshmukh
Vaibhav Deshmukh

Reputation: 33

int maxlength = 10;
String message = "1234567890ABCDEFGHIJKLMNOPQRSTUVWXYZ";
String transformedMessage = message.replaceAll("(?<=\\G.{" + maxlength + "})", "\n");
System.out.println(transformedMessage);
/*Output
1234567890
ABCDEFGHIJ
KLMNOPQRST
UVWXYZ
*/

Upvotes: 0

the Hutt
the Hutt

Reputation: 18408

Use WordIterator like this. BreakIterator classes are locale sensitive. You can use with different languages.

public static void main(String[] args) {
    String msg = "This is a long message. Message is too long. Long is the message";
    int widthLimit = 15;
    printWithLimitedWidth(msg, widthLimit);
}

static void printWithLimitedWidth(String s, int limit) {
    BreakIterator br = BreakIterator.getWordInstance(); //you can get locale specific instance to handle different languages.
    br.setText(s);
    int currLenght = 0;
    int start = br.first();
    int end = br.next();

    while (end != BreakIterator.DONE) {
       String word = s.substring(start,end);
       currLenght += word.length(); 
       if (currLenght <= limit) {
          System.out.print(word);
       } else {
           currLenght = 0;
           System.out.print("\n"+word);
       }
       start = end;
       end = br.next();
    }
}

Output:

This is a long 
message. Message is 
too long. Long is 
the message

This is a sample code. Handle white space and other special characters according to your needs. For more info refer https://docs.oracle.com/javase/tutorial/i18n/text/about.html

Upvotes: 2

markspace
markspace

Reputation: 11030

This sort of works. I picked a very short "line" length of 10 characters, you should probably increase this. But it shows how you might do this without too much code. Cheange the "10" in the regex to a different number to increase the line length.

(I changed the code a bit to make it more obvious that this method does not split words in the middle but always splits at a white space.)

   public static void main( String[] args ) {
      String s = "This is a test. This is a test. This is a test. This is a test. This is a test. This is a test.  ";
      String regex = ".{1,10}\\s";
      Matcher m = Pattern.compile( regex ).matcher( s );
      ArrayList<String> lines = new ArrayList<>();
      while( m.find()  ) {
         lines.add(  m.group() );
      }
      System.out.println( String.join( "\n", lines ) );
   }

run:

This is a 
test. This 
is a test. 
This is a 
test. This 
is a test. 
This is a 
test. This 
is a test. 
BUILD SUCCESSFUL (total time: 0 seconds)

Upvotes: 1

Spectric
Spectric

Reputation: 31992

Regex version (simplest):

String text = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book.";
int lineMaxLength = 10;
System.out.println(java.util.Arrays.toString(
    text.split("(?<=\\G.{"+lineMaxLength+"})")
));

Which prints:

[Lorem Ipsu, m is simpl, y dummy te, xt of the , printing a, nd typeset, ting indus, try. Lorem,  Ipsum has,  been the , industry's,  standard , dummy text,  ever sinc, e the 1500, s, when an,  unknown p, rinter too, k a galley,  of type a, nd scrambl, ed it to m, ake a type,  specimen , book.]

Without regex:

import java.util.List;
import java.util.ArrayList;

public class MyClass {
    public static void main(String args[]) {
      String text = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book.";
      int lineMaxLength = 10;
      List<String> lines = new ArrayList<>();
      int length = text.length();
      StringBuilder s = new StringBuilder();
      for(int i = 0; i < length; i++){
          if (i % lineMaxLength == 0){
              if(i != 0){
                  lines.add(s.toString());
              }
              s = new StringBuilder();
          }
          s.append(text.charAt(i));
      }
  int linesLength = lines.size();
  for(int i= 0; i < linesLength; i++){
      System.out.println(lines.get(i));
  }
    }
}

Which prints:

Lorem Ipsu
m is simpl
y dummy te
xt of the 
printing a
nd typeset
ting indus
try. Lorem
 Ipsum has
 been the 
industry's
 standard 
dummy text
 ever sinc
e the 1500
s, when an
 unknown p
rinter too
k a galley
 of type a
nd scrambl
ed it to m
ake a type
 specimen

Upvotes: 1

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