Reputation: 31
is it possible to get the coordinates of the incomplete circle? i am using opencv and python. so i can find the most of the circles. But i have no clue how can i detect the incomplete cirlce in the picture. I am looking for a simple way to solve it.
import sys
import cv2 as cv
import numpy as np
## [load]
default_file = 'captcha2.png'
# Loads an image
src = cv.imread(cv.samples.findFile(default_file), cv.IMREAD_COLOR)
## [convert_to_gray]
# Convert it to gray
gray = cv.cvtColor(src, cv.COLOR_BGR2GRAY)
## [convert_to_gray]
## [reduce_noise]
# Reduce the noise to avoid false circle detection
gray = cv.medianBlur(gray, 3)
## [reduce_noise]
## [houghcircles]
#rows = gray.shape[0]
circles = cv.HoughCircles(gray, cv.HOUGH_GRADIENT, 1, 5,
param1=1, param2=35,
minRadius=1, maxRadius=30)
## [houghcircles]
## [draw]
if circles is not None:
circles = np.uint16(np.around(circles))
for i in circles[0, :]:
center = (i[0], i[1])
# circle center
cv.circle(src, center, 1, (0, 100, 100), 3)
# circle outline
radius = i[2]
cv.circle(src, center, radius, (255, 0, 255), 3)
## [draw]
## [display]
cv.imshow("detected circles", src)
cv.waitKey(0)
## [display]
Hi - there is an other Picture. I want the x and y cords of the incomplete circle, light blue on the lower left.
Here the original Pic:
Upvotes: 2
Views: 2457
Reputation: 7985
You need to remove the colorful background of your image and display only circles.
One approach is:
Get the binary mask of the input image
Apply Hough Circle to detect the circles
Binary mask:
Using the binary mask, we will detect the circles:
Code:
# Load the libraries
import cv2
import numpy as np
# Load the image
img = cv2.imread("r5lcN.png")
# Copy the input image
out = img.copy()
# Convert to the HSV color space
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
# Get binary mask
msk = cv2.inRange(hsv, np.array([0, 0, 130]), np.array([179, 255, 255]))
# Detect circles in the image
crc = cv2.HoughCircles(msk, cv2.HOUGH_GRADIENT, 1, 10, param1=50, param2=25, minRadius=0, maxRadius=0)
# Ensure circles were found
if crc is not None:
# Convert the coordinates and radius of the circles to integers
crc = np.round(crc[0, :]).astype("int")
# For each (x, y) coordinates and radius of the circles
for (x, y, r) in crc:
# Draw the circle
cv2.circle(out, (x, y), r, (0, 255, 0), 4)
# Print coordinates
print("x:{}, y:{}".format(x, y))
# Display
cv2.imshow("out", np.hstack([img, out]))
cv2.waitKey(0)
Output:
x:178, y:60
x:128, y:22
x:248, y:20
x:378, y:52
x:280, y:60
x:294, y:46
x:250, y:44
x:150, y:62
Explanation
We have three chance for finding the thresholding:
As we can see the third option gave us a suitable result. Of course, you could get the desired result with other options, but it might take a long time for finding the suitable parameters. Then we applied Hough circles, played with parameter values, and got the desired result.
Update
For the second uploaded image, you can detect the semi-circle by reducing the first and second parameters of the Hough circle.
crc = cv2.HoughCircles(msk, cv2.HOUGH_GRADIENT, 1, 10, param1=10, param2=15, minRadius=0, maxRadius=0)
Replacing the above line in the main code will result in:
Console result
x:238, y:38
x:56, y:30
x:44, y:62
x:208, y:26
Upvotes: 1