CODEWITHSUNDEEP
cstdoutbuffering
JustSomeGuy
JustSomeGuy

Reputation: 123

Setting C program to line buffer won't work

I'm trying to force my C program to line buffer (stdout is going to be captured by a java program), but it always seems to fully buffer instead. Here is some sample code:

#include <stdio.h>
#include <stdlib.h>

int main(){
    char c;
    setvbuf(stdout, NULL, _IOLBF, BUFSIZ);
    printf("Hello world\n");
    c = getchar();
    printf("got char: %c\n", c);
}

If I specify _IOLBF or _IOFBF, then I don't see an output until I input a char. Only if I use _IONBF will I see output before the getchar(). Shouldn't _IOLBF do the same since "Hello World\n" contains a '\n'?

I am using visual c++ 2005.

Thanks

Upvotes: 1

Views: 634

Answers (1)

Ben Jackson
Ben Jackson

Reputation: 93690

According to this Microsoft documentation:

_IOLBF: For some systems, this provides line buffering. However, for Win32, the behavior is the same as _IOFBF - Full Buffering.

Upvotes: 3

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