Reputation: 1545
I have the following array seen in full at ARRAY 1, I need each subarray to merge the objects within it such that it is like so.
ARRAY FINAL
[
{"col0":"glasses","col1":"Milky glasses","col2":"292516467012796941"}
, ...
]
So the end result is one array with 6 objects. The ... above represents the rest of the objects.
I have tried [].concat.apply([], array)
but it doesn't do quite what I want. I will post what it does below this array at ARRAY 2
ARRAY 1
[
[
{
"col0": "Glasses"
},
{
"col1": "Milky Glasses"
},
{
"col2": "292516467012796941"
}
],
[
{
"col0": "Knives"
},
{
"col1": "Milky Knives"
},
{
"col2": "292516484536599049"
}
],
[
{
"col0": "Forks"
},
{
"col1": "Milky Forks"
},
{
"col2": "292516497196057096"
}
],
[
{
"col0": "Gloves"
},
{
"col1": "Kewl Gloves"
},
{
"col2": "292534063457108493"
}
],
[
{
"col0": "Wrench"
},
{
"col1": "Kewl Wrench"
},
{
"col2": "292534088244396552"
}
],
[
{
"col0": "Monkey snake"
},
{
"col1": "Kewl Monkey snake"
},
{
"col2": "292534109863936521"
}
]
]
This is the output that I don't want, but all I could manage thus far. See the output I do want at the top at ARRAY FINAL
ARRAY 2
[
{
"col0": "Glasses"
},
{
"col1": "Milky Glasses"
},
{
"col2": "292516467012796941"
},
{
"col0": "Knives"
},
{
"col1": "Milky Knives"
},
{
"col2": "292516484536599049"
},
{
"col0": "Forks"
},
{
"col1": "Milky Forks"
},
{
"col2": "292516497196057096"
},
{
"col0": "Gloves"
},
{
"col1": "Kewl Gloves"
},
{
"col2": "292534063457108493"
},
{
"col0": "Wrench"
},
{
"col1": "Kewl Wrench"
},
{
"col2": "292534088244396552"
},
{
"col0": "Monkey snake"
},
{
"col1": "Kewl Monkey snake"
},
{
"col2": "292534109863936521"
}
]
Thanks for any help ahead of time
Upvotes: 2
Views: 61
Reputation: 137
Nina has the best answer, but it's worth noting that Object.assign() is a shallow copy.
If the col properties were objects themselves you could use an approach like the one below:
const finish = start.map((x) => ({
...x[0],
...x[1],
...x[2]
}));
If I understand correctly, the ...x[0] syntax creates a deep copy of x[0] and we assign that directly to our new object, whereas Object.assign() creates a shallow copy.
Upvotes: 0
Reputation: 659
That could be accomplished like so, with arr
being your original array -
for (let i = 0; i < arr.length; i++) {
let res = {}, subArr = arr[i];
subArr.forEach((a,ind) => {
Object.assign(res,subArr[0],subArr[1],subArr[2]);
});
arr[i] = res;
}
Upvotes: 0
Reputation: 386786
You could map the array and spread the objects for getting a single object.
const
data = [[{ col0: "Glasses" }, { col1: "Milky Glasses" }, { col2: 292516467012796900 }], [{ col0: "Knives" }, { col1: "Milky Knives" }, { col2: 292516484536599040 }], [{ col0: "Forks" }, { col1: "Milky Forks" }, { col2: 292516497196057100 }], [{ col0: "Gloves" }, { col1: "Kewl Gloves" }, { col2: 292534063457108500 }], [{ col0: "Wrench" }, { col1: "Kewl Wrench" }, { col2: 292534088244396540 }], [{ col0: "Monkey snake" }, { col1: "Kewl Monkey snake" }, { col2: 292534109863936500 }]],
result = data.map(a => Object.assign({}, ...a));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Upvotes: 5