CODEWITHSUNDEEP
python-3.xlistif-statementwhile-loopappend
pfft khaganate
pfft khaganate

Reputation: 111

How to append values in a while loop by using an if statement

records = [["chi", 20.0],["beta", 50.0],["alpha", 50.0]]
a = len(records)
i = 0
b = []
while i < a:
    print(records[i][1])
    b.append(records[i][1])
    i = i + 1
print(b)
c = len(b)
#from previous question
unique_list = []
for el in b:
   if el not in unique_list:
       unique_list.append(el)
   else:
       print ("Element already in the list")
print(unique_list)
second_lowest_score = unique_list[1]
print(second_lowest_score)
names_list = []
g = 0
while g < a:
    if records[g][1] == second_lowest_score:
        names_list.append(records[g][0])
        g = g + 1
print(names_list)

What I want to do is to append the names of records which have the second lowest score (50) to the names_list. However, the while loop gives me no result. There is no syntax error so I am not sure why my code is wrong. However, when I use the previous while loop for appending the numbers, it seems to work fine. Is it not possible to use an if statement in a while loop?

Upvotes: 0

Views: 1050

Answers (1)

Luke B
Luke B

Reputation: 2121

This is a pretty simple problem. The g variable is not getting incremented if the if statement does not run, so the loop will endlessly continue on the same value of g.

The fix for this is to move the increment of g outside of the if statement (but still in the while loop). That way it will continue past values even if they do not match the if condition.

if records[g][1] == second_lowest_score:
    names_list.append(records[g][0])
g = g + 1

Upvotes: 1

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