NaturalDevCR
NaturalDevCR

Reputation: 852

Calculate the best distribution for a group of numbers that can FIT on a specific number

I have what I think is a interesting question, about google sheets and some Maths, here is the scenario:

4 numbers as follows:

64.20 | 107 | 535 | 1070

A reference number in which the previous numbers needs to fit leaving the minimum possible residue while setting the number of times each of them fitted in the reference number for example we could say the reference number is the following:

806.45

So here is the problem:

I'm calculating how many times those 4 numbers can fit in the reference number by starting from the higher to the lower number like this:

| 1070 | => =IF(E12/((I15+J15)+IF(H17,K17,0)+IF(H19,K19,0)) > 0,ROUNDDOWN(E12/((I15+J15)+IF(H17,K17,0)+IF(H19,K19,0))),0)

| 535 | => =IF(H15>0,ROUNDDOWN((E12-K15-IF(H17,K17,0)-IF(H19,K19,0))/(I14+J14)),ROUNDDOWN(E12/((I14+J14)+IF(H17,K17,0)+IF(H19,K19,0))))

| 107 | => =IF(OR(H15>0,H14>0),ROUNDDOWN((E12-K15-K14-IF(H17,K17,0)-IF(H19,K19,0))/(I13+J13)),ROUNDDOWN((E12-IF(H17,K17,0)-IF(H19,K19,0))/(I13+J13)))

| 64.20 | => =IF(OR(H15>0,H14>0,H13>0),ROUNDDOWN((E12-K15-K14-K13-IF(H17,K17,0)-IF(H19,K19,0))/(I12+J12)),ROUNDDOWN((E12-IF(H17,K17,0)-IF(H19,K19,0))/(I12+J12)))

As you can notice, I'm checking if the higher values has a concurrence, so I can substract the amount from the original number and calculate again how many times can fit the lower number in the result of that subtraction , you can also see that I'm including some checkboxes to the formula in order to add a fixed number to the main number.

This actually works, and as you can see in the example, the result is:

| 1070 | -> Fits 0 times

| 535 | -> Fits 1 time

| 107 | -> Fits 2 times

| 64.20 | -> Fits 0 times

The residue of 806.45 in this example is: 57.45


But each number that needs to fit on the main number needs to take in consideration others; IF you solve this exercise manually, you could get something much better.. like this:

| 1070 | -> Fits 0 times

| 535 | -> Fits 1 time

| 107 | -> Fits 0 times

| 64.20 | -> Fits 4 times

The residue of 806.45 in this example is: 14.65

When I’m talking about residue I mean the result when subtracting, I’m sorry if this is not clear, it’s hard to me to explain maths in English, since is not my native language, please see the spreadsheet and make a copy to better understand what I’m trying to do, or suggest me a way to explain it better if possible.

So what would you do to make it work more efficient and "smart" with the minimum possible residue after the calculation?

Here is the Google's spreadsheet for reference and practice, please make a copy so others can try their own solutions:

LINK TO SPREADSHEET

Thanks in advance for any help or hints.

Upvotes: 0

Views: 182

Answers (1)

Erik Tyler
Erik Tyler

Reputation: 9345

Delete all current formulas in H12:H15.

Then place this mega-formula in H12:

=ArrayFormula(QUERY(SPLIT(FLATTEN(SPLIT(VLOOKUP(E12,QUERY(SPLIT(FLATTEN(QUERY(SPLIT(FLATTEN(QUERY(SPLIT(FLATTEN(SEQUENCE(ROUNDUP(E12/I12),1,0)&" "&I12&" / "&TRANSPOSE(SEQUENCE(ROUNDUP(E12/I13),1,0)&" "&I13)&"|"&(SEQUENCE(ROUNDUP(E12/I12),1,0)*I12)+(TRANSPOSE(SEQUENCE(ROUNDUP(E12/I13),1,0)*I13))),"|"),"Select Col1")&" / "&TRANSPOSE(SEQUENCE(ROUNDUP(E12/I14),1,0)&" "&I14)&"|"&QUERY(SPLIT(FLATTEN(SEQUENCE(ROUNDUP(E12/I12),1,0)&" "&I12&" / "&TRANSPOSE(SEQUENCE(ROUNDUP(E12/I13),1,0)&" "&I13)&"|"&((SEQUENCE(ROUNDUP(E12/I12),1,0)*I12)+(TRANSPOSE(SEQUENCE(ROUNDUP(E12/I13),1,0)*I13)))),"|"),"Select Col2")+TRANSPOSE(SEQUENCE(ROUNDUP(E12/I14),1,0)*I14)),"|"),"Select Col1")&" / "&TRANSPOSE(SEQUENCE(ROUNDUP(E12/I15),1,0)&" "&I15)&"|"&QUERY(SPLIT(FLATTEN(QUERY(SPLIT(FLATTEN(SEQUENCE(ROUNDUP(E12/I12),1,0)&" "&I12&" / "&TRANSPOSE(SEQUENCE(ROUNDUP(E12/I13),1,0)&" "&I13)&"|"&(SEQUENCE(ROUNDUP(E12/I12),1,0)*I12)+(TRANSPOSE(SEQUENCE(ROUNDUP(E12/I13),1,0)*I13))),"|"),"Select Col1")&" / "&TRANSPOSE(SEQUENCE(ROUNDUP(E12/I14),1,0)&" "&I14)&"|"&QUERY(SPLIT(FLATTEN(SEQUENCE(ROUNDUP(E12/I12),1,0)&" "&I12&" / "&TRANSPOSE(SEQUENCE(ROUNDUP(E12/I13),1,0)&" "&I13)&"|"&((SEQUENCE(ROUNDUP(E12/I12),1,0)*I12)+(TRANSPOSE(SEQUENCE(ROUNDUP(E12/I13),1,0)*I13)))),"|"),"Select Col2")+TRANSPOSE(SEQUENCE(ROUNDUP(E12/I14),1,0)*I14)),"|"),"Select Col2")+TRANSPOSE(SEQUENCE(ROUNDUP(E12/I15),1,0)*I15)),"|"),"Select Col2, Col1 WHERE Col2 <= "&E12&" ORDER BY Col2 Asc, Col1 Desc"),2,TRUE)," / ",0,0))," "),"Select Col1"))

Typically, I explain my formulas. In this case, I trust that readers will understand why I cannot explain it. I can only offer it in working order.

To briefly give the general idea, this formula figures out how many times each of the four numbers fits into the target number alone and then adds every possible combination of all of those. Those are then limited to only the combinations less than the target number and sorted smallest to largest in total. Then a VLOOKUP looks up the target number in that list, returns the closest match, SPLITs the multiples from the amounts (which, in the end, have been concatenated into long strings), and returns only the multiples.

Upvotes: 1

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