CODEWITHSUNDEEP
scala
Mah
Mah

Reputation: 105

Scala compilation error when running sys.process._

I am trying to run compile below function in scala

  import java.io.{File, PrintWriter, StringWriter}
  def runCommand(cmd:String):(Int,String)={
      try {
        logger.info(String.format("Trying to run the following bash command: [%s]", cmd))
        import sys.process._
        val intResult:Int = cmd !
        val stringResult:String = cmd !!
        (intResult, stringResult)
      }
      catch {
        case e: Exception => {
          logger.error(String.format("Error in running the following bash command: [%s], Program exits!", cmd))
          val sw = new StringWriter
          e.printStackTrace(new PrintWriter(sw))
          System.out.println(sw.toString)
          sys.exit(1)
        }
      }
    (1,"1")
  }

But, I am getting below error:

[ERROR] [Error] C:\Users\cp740539\IdeaProjects\sparkscala\src\main\scala\au\com\optus\bdp\conversion\PurgingPartitions.scala:213: overloaded method value !! with a
lternatives:
  (log: scala.sys.process.ProcessLogger)String <and>
  => String
 cannot be applied to (Int, String)

I am not sure what is the cause of the erro?

Upvotes: 1

Views: 308

Answers (1)

jwvh
jwvh

Reputation: 51271

You're using the dot-less instance method arg syntax without the arg. The compiler goes looking for the arg and finds the (intResult,stringResult) tuple and tries to pass that to the !! method, which doesn't work.

Use cmd.! and cmd.!! instead.

Also: If you use a ProcessLogger then you can capture the exit code (Int), as well as StdOut and StdErr (Strings), with a single execution of cmd instead of invoking it twice, as you are doing now.

Upvotes: 2

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