Reputation: 35
I have a table tab
that has cols date,sym,value
and is sorted from oldest date to the recent.
I am trying to select the past N
records for each sym
and am not sure of the query for this. I know that I can select based on date
being within a range but I needed it based on sym
irrespective if value
appeared on consecutive dates or not.
Upvotes: 1
Views: 664
Reputation: 3179
Matt's suggestions using an fby
and functional select are best if you want all columns in the table returned. If you only need the date
, sym
& price
columns returned you could use
q)ungroup select -2#date,-2#price by sym from trade
sym date price
----------------------
APPL 2021.03.13 111.77
APPL 2021.03.13 111.85
CAT 2021.03.13 246
CAT 2021.03.13 246.27
GOOG 2021.03.13 206.24
GOOG 2021.03.13 206.21
NYSE 2021.03.13 60.67
NYSE 2021.03.13 60.97
Note that this can become tedious when selecting a large number of columns. In those cases it's better to stick with Matt's suggestions.
Upvotes: 2
Reputation: 2775
You could do this with fby
and the virtual row number column i
:
https://code.kx.com/q/ref/fby/
q){ select from tab where ({y in x#y}[x];i) fby sym }[-2]
date sym time src price size
------------------------------------------------------------
2014.04.21 AAPL 2014.04.21D16:29:03.253000000 N 24.98 3561
2014.04.21 AAPL 2014.04.21D16:29:03.558000000 N 24.98 2733
2014.04.21 CSCO 2014.04.21D16:28:56.265000000 O 35.6 8390
2014.04.21 CSCO 2014.04.21D16:29:44.572000000 L 35.61 2286
2014.04.21 DELL 2014.04.21D16:29:35.374000000 L 29.57 1444
2014.04.21 DELL 2014.04.21D16:29:39.979000000 N 29.56 216
2014.04.21 GOOG 2014.04.21D16:29:50.569000000 N 41.87 722
2014.04.21 GOOG 2014.04.21D16:29:58.633000000 O 41.9 437
Edit: Faster way would be to use functional exec with the 5th argument n(number of records) for each sym.
raze{
//[table;where;by;cols;rows]
?[tab;enlist (in;`sym;enlist x);0b;();y]
}[;-2]'[distinct tab[`sym]]
https://code.kx.com/q/basics/funsql/
Upvotes: 2