Reputation: 11317
Note: The code is using spread syntax
, not rest parameters
.
const fn1 = undefined
const args = []
const fn2 = () => {}
const fn3 = () => {}
console.log(fn1?.(...args, fn2, fn3))
Error:
console.log(fn1?.(...args, fn2, fn3))
^
TypeError: Function.prototype.apply was called on undefined, which is an undefined and not a function
Upvotes: 16
Views: 3969
Reputation: 11317
It turns out to be a V8 bug, I've submitted it there, hopefully, it'll be fixed soon.
Update: it has been fixed.
Upvotes: 10
Reputation: 7985
There are a couple rules to follow with ...rest arguments.
One of those rules is that the ...rest argument can only be the last argument.
foo(...one, ...wrong, ...wrong)
foo(...wrong, bad, bad)
foo(ok, ok, ...correct)
See:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Functions/rest_parameters
Upvotes: -4