CODEWITHSUNDEEP
kotlin
user12880465
user12880465

Reputation:

Kotlin – Add 'hashMapOf' to Array

Coming from PHP it's beyond annoying to deal with all kind of array types in Kotlin/Java like listOf mutableListof arrayOf mutableArrayOf etc

I just want be able to add values (hashMapOf) to a damn array.

After initializing array (if it's even an array or what ever):

val bla = mutableListOf(hashMapOf<Long, Int>())

I tried those:

bla.add(5L to 7)
bla.add(5L, 7)
bla += 5L to 7

how to do this right??

What I basically want:

val bla = array()

bla.add(4L, 7)
bla.add(5L, 8)
bla.add(6L, 9)

and then:

Log.d("tag", "get long from second: " + bla[1].getTheLong) // 5L
Log.d("tag", "get int from second: " + bla[1].getTheInt) // 8

Upvotes: 1

Views: 269

Answers (3)

Rubydesic
Rubydesic

Reputation: 3476

From you edit it becomes clear you want

val blah = mutableListOf<Pair<Long, Int>>()
blah.add(Pair(4L, 7))
blah.add(Pair(5L, 7)) // equivalent to blah.add(5L to 7)

and then

Log.d("tag", "get long from second: " + bla[1].first) // 5L
Log.d("tag", "get int from second: " + bla[1].second) // 8

Upvotes: 0

Dominik
Dominik

Reputation: 1741

Currently, in your code, bla is a List<HashMap<Long, Int>>.

I guess you want to have a HashMap<Long, Int>, which would result in this:

val bla = mutableMapOf<Long, Int>()
bla.put(7, 2);    
print(bla.get(0))

or you want to have a List<Pair<Long, Int>>, which results in this:

val bla = mutableListOf<Pair<Long,Int>>()
bla.add(Pair(7, 2))     
print(bla.get(0))

The difference is, that for a map each key must be unique. The list of pairs allows you to add multiple pairs that are equal.

Upvotes: 1

Andy Jazz
Andy Jazz

Reputation: 58563

Try the following solution:

fun main() {

    val bla = mutableListOf(hashMapOf<Long, Int>())
    
    bla[0][0] = 5
    bla[0][1] = 7
    
    println(bla)
}

// Result:  [ { 0=5, 1=7 } ]

Upvotes: 0

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