CODEWITHSUNDEEP
c++arrays
potato_girl
potato_girl

Reputation: 19

printing vowels in c++ char array

i made this code to print out vowels from array. i have wrote code before but back then only error was that it was printing whole array instead of just vowels. i wrote it today again i dont think that 2nd time i have made any change in code than the previous one(if i made i cant see) but now it takes blank input of array and ends the program. can u help me out? here is the code:

int size=0;
    cout<<"Enter the size of array=";
    cin>>size;
    char arr[size];
    cout<<"Enter the array=";
    for(int i=0;arr[i]='\0';i++){
        cin>>arr[i];
    }
    for(int i=0;arr[i]!='\0';i++)
    {
        if(arr[i]=='a'||'e'||'i'||'o'||'u'||'A'||'E'||'I'||'O'||'U')
        {
            cout<<arr[i];
        }
    }

Upvotes: 2

Views: 1426

Answers (1)

Zach_Mose
Zach_Mose

Reputation: 357

Try this:

#include <iostream>
using namespace std;

int main()
{
    int size = 0;
    cout << "Enter the size of array=";
    cin >> size;
    char *arr= new char[size]; /*Requires a pointer to declare a dynamic array or a vector*/
    cout << "Enter the letters array " <<endl;
    for (int i = 0; i < size; i++) {
        cout << i + 1 << " : ";
        cin >> arr[i];
    }
    for (int i = 0; i < size; i++)
    {
        switch (arr[i])
        {   case 'a' :
            case 'A':
            case 'e':
            case 'E':
            case 'i':
            case 'I':
            case 'o':
            case 'O':
            case 'u':
            case 'U':
                cout << arr[i];
            break;
        default:
            break;
        }
    }
}

Upvotes: 3

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