CODEWITHSUNDEEP
pythonstring
userX
userX

Reputation: 23

How to replace each letter in a string with a consecutive letter with increasing offset?

Suppose the word is "CAT" and I want the output to be "DCW". Where the C changes to the next letter D and the A changes into the second next letter from A to C and the T changes into the third next letter from T to W.

I am on the first step here:

a = input("Enter a letter: ")
a = chr(ord(a) + 1)
print(a)

Upvotes: 1

Views: 68

Answers (3)

Maurice Meyer
Maurice Meyer

Reputation: 18126

You need to loop over the word:

word = 'CAT'
result = ''
for i, a in enumerate(word,1):
    result += chr(ord(a) + i)
print(result)

# alternatively, same loop as list comprehension
print(''.join(chr(ord(a) + i) for i, a in enumerate(word,1)))

Out:

DCW
DCW

Upvotes: 1

Belhadjer Samir
Belhadjer Samir

Reputation: 1659

try this :

import string
a =input("Enter a letter: ")
r=''
for i,e in enumerate(a,1):
   r=r+string.ascii_lowercase[string.ascii_lowercase.index(e.lower())+i]
print(r.upper())

or in one line like this :

print(''.join(list(string.ascii_lowercase[string.ascii_lowercase.index(e.lower())+i] for i,e in enumerate(a,1) )).upper())

Note: in Python 2, string.ascii_lowercase is string.lowercase.

Upvotes: 0

Peter Ferencz
Peter Ferencz

Reputation: 74

What you are looking for is called Caesar cypher, but the offset changes with the character's position:

    def encrypt(text):
    result = ""
    for i in range(len(text)):
        char = text[i]
        if (char.isupper()):
            result += chr((ord(char) -65) % 26 + 65 + i + 1)
        else:
            result += chr((ord(char) - 97) % 26 + 97 + i + 1)
    return result

print(encrypt(input()))

Source: https://www.tutorialspoint.com/cryptography_with_python/cryptography_with_python_caesar_cipher.htm

Upvotes: 0

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