CODEWITHSUNDEEP
c
nareto
nareto

Reputation: 185

unsigned long long int strange behaviour

this C code

unsigned long int a, b, x;
float c, d, y;

a = 6;
b = 2;
x = a/b;

c = 6.0;
d = 2.0;
y = c/d;

printf("\n x: %d \n y: %f \n",x,y);

works correctly and prints out

x: 3 
y: 3.000000

however, when I change the first line to this

unsigned long long int a, b, x;

I get this output:

x: 3 
y: 0.000000

this really boggles me... I haven't changed anything with c,d, and y - why am I getting this? I'm using gcc on linux

Upvotes: 4

Views: 254

Answers (2)

Mihran Hovsepyan
Mihran Hovsepyan

Reputation: 11098

You should use:

printf("\n x: %llu \n y: %f \n", x, y);

Otherwise something like this will happen (example is for system where unsigned long int is 4 byte, unsigned long long int is 8 byte and float is 4 byte):

  1. [[03 00 00 00] (unsigned long int) [3.0] (float)] everything is correct, you print two 4 byte values.
  2. [[03 00 00 00 00 00 00 00] (unsigned long long int) [3.0] (float)] here, you print two 4 print values, but actually in the buffer that your printf received there is one 8 byte value and one 4 byte value, so you prints only first 8 bytes :)

Upvotes: 2

Karoly Horvath
Karoly Horvath

Reputation: 96258

For the latter one use:

printf("\n x: %llu \n y: %f \n",x,y);

Use u for unsigned integrals (your output is only correct because you use small values). Use the ll modifier for long longs otherwise printf will use the wrong size for decoding the second parameter (x) for printf, so it uses bad address to fetch y.

Upvotes: 7

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