CODEWITHSUNDEEP
bashstdoutstderrsubshell
pico_prob
pico_prob

Reputation: 1365

How to capture / redirect stdout/stderr from a source command into a variable (in a bash script)?

Usually I capture the output via a subshell: result="$(command 2>&1)"

If the command is source, the subshell swallows some (all?) changes to the scripts shell's environment.

How can I capture the output of source into a variable?

Upvotes: 6

Views: 2308

Answers (1)

Thomas
Thomas

Reputation: 181745

Surprisingly tricky question!

My first thought was to use a named pipe (mkfifo(1)), but those have a finite buffer size, so if the sourced script fills up the buffer the script would hang. And you can't use a background process to drain the buffer because you want the output in a variable in the original process eventually.

I'm sure there's a way to make it work entirely in memory, but in the end I think a simple and stupid redirect to a temporary file is the most straightforward and robust solution:

OUTPUT_FILE=$(mktemp)
source other_script.sh >$OUTPUT_FILE 2>&1
OUTPUT="$(< "$OUTPUT_FILE")"
rm -f "$OUTPUT_FILE"

(See this question and in particular BashFAQ 062 for security implications of mktemp though.)

Upvotes: 10

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